如何在字符串中每6個空格添加一個“ \\ n”？

Question

我在多維數組中有很長的字符串。 我一直試圖找出一種方法，用"\\n"替換每個字符串中的每個第6個空格，這將導致它基本上按回車鍵。

例：
orginalString =“我要在此的第六個空格之后放置回車”;

FormatedString =“我要在\\ n的第六個空格之后輸入enter”

這就是我到目前為止所得到的。 可能完全錯誤。

public static void FormatArray(String c) {
    int counter = 0;
    for (int i = 0; i < c.length(); i++) {
        if (c.charAt(i) == ' ') {
            counter++;
        }
        if (counter == 6) {
            counter = 0;
            for (int j = 0; j < Variables.getCards().length; j++) {
                StringBuilder string = new StringBuilder(
                                                    Variables.getCards()[j][1]);
                string.setCharAt(i, '\n');
                System.out.println(string);
            }
        }
    }
}

Answer 1

這是一種解決方案：

str = str.replaceAll("(\\S+\\s+){6}", "$0\n");

替換項$0是整個匹配項，因此會返回匹配項和換行符。

如果正則表達式不符合您的喜好，請更改它。 例如，如果要用換行符替換第6個空格，請從捕獲中排除尾隨空格：

str = str.replaceAll("((\\S+\\s+){5}\\S+)\\s+", "$1\n");

Answer 2

我會這樣做

// given a String str, replace every sixth space with " \n "
public static String formatString(String str) {
  if (str == null) {                         // Handle null.
    return null;
  }
  StringBuilder sb = new StringBuilder();    // An output buffer.
  int count = 0;
  for (char ch : str.toCharArray()) {        // loop over the characters.
    if (ch == ' ') {                         // test for space.
      count++;
    }
    if (count == 6) {                        // every sixth space.
      count = 0;
      sb.append(" \n");
    }
    sb.append(ch);
  }
  return sb.toString();                      // return the string.
}

// Test it.
public static void main(String[] args) {
  String originalString = "i want to put enter after the sixth space of this";
  String formattedString = "i want to put enter after \n the sixth space of this";
  if (formatString(originalString).equals(
      formattedString)) {
    System.out.println("Yes");
  } else {
    System.out.println("No");
  }
}

當我運行上面的代碼時，我得到的輸出-

Yes

Answer 3

你說得很對。 我建議以下內容：

public static String formatStr(String a){
    if(a==null) return null;
    String newStr="";
    int len=a.length();
    int counter=0;
    for(int i=0;i<len;i++){
        newStr+=a.charAt(i);
        if (a.charAt(i) == ' ')counter++;

        if (counter == 6){
            counter=0;
            newStr+="\n";
            //System.out.println(string);
        }
    }
    return newStr;
}

然后，您可以調用formatStr（whatever），您將獲得返回的字符串。

Answer 4

您可以使用以下正則表達式：

    String pattern = "(\\S*\\s){6}";
    String testString = "This is just a regular test. This is just a regular test. This is just a regular test.";

    Pattern p = Pattern.compile(pattern);
    Matcher matcher = p.matcher(testString);
    StringBuilder strBuilder = new StringBuilder();

    while (matcher.find()) {
        strBuilder.append(matcher.group());
        strBuilder.replace(strBuilder.length() - 1, strBuilder.length(), "\n"); // To make it platform independent, user System.lineSeparator() instead of "\n" - only works in Java 7
    }

    if (matcher.hitEnd()) {
        strBuilder.append(testString.substring(strBuilder.length()));
    }

    String newString = strBuilder.toString();
    System.out.println(newString);

輸出將是：

This is just a regular test.
This is just a regular test.
This is just a regular test.