將mysql行數據存儲到php變量名稱和值中

Question

我需要將sql查詢中的值存儲到變量中的幫助。 問題是為了獲得合適的值，我不得不寫一個長的UNION查詢。 只有兩列，結果也不多。 理想情況下，我想為每一行創建一個變量，其中變量名稱是第一列的結果，而該變量的相應值將是第二列的結果。

這是UNION查詢：

SELECT 'mon_m' as shift, count(mon_m) as count
FROM schedule
WHERE week_of = '2013-12-23'
AND mon_m <> ''

UNION

SELECT 'mon_a', COUNT(mon_a) 
FROM schedule
WHERE week_of = '2013-12-23'
AND mon_a <> ''

UNION

SELECT 'mon_n', COUNT(mon_n)
FROM schedule
WHERE week_of = '2013-12-23'
AND mon_n <> ''

UNION

SELECT 'tue_m', count(tue_m) 
FROM schedule
WHERE week_of = '2013-12-23'
AND tue_m <> ''

UNION

SELECT 'tue_a', COUNT(tue_a) 
FROM schedule
WHERE week_of = '2013-12-23'
AND tue_a <> ''

UNION

SELECT 'tue_n', COUNT(tue_n)
FROM schedule
WHERE week_of = '2013-12-23'
AND tue_n <> ''

UNION

SELECT 'wed_m', count(wed_m) 
FROM schedule
WHERE week_of = '2013-12-23'
AND wed_m <> ''

UNION

SELECT 'wed_a', COUNT(wed_a) 
FROM schedule
WHERE week_of = '2013-12-23'
AND wed_a <> ''

UNION

SELECT 'wed_n', COUNT(wed_n)
FROM schedule
WHERE week_of = '2013-12-23'
AND wed_n <> ''

UNION

SELECT 'thu_m', count(thu_m) 
FROM schedule
WHERE week_of = '2013-12-23'
AND thu_m <> ''

UNION

SELECT 'thu_a', COUNT(thu_a) 
FROM schedule
WHERE week_of = '2013-12-23'
AND thu_a <> ''

UNION

SELECT 'thu_n', COUNT(thu_n)
FROM schedule
WHERE week_of = '2013-12-23'
AND thu_n <> ''

UNION

SELECT 'fri_m', count(fri_m) 
FROM schedule
WHERE week_of = '2013-12-23'
AND fri_m <> ''

UNION

SELECT 'fri_a', COUNT(fri_a) 
FROM schedule
WHERE week_of = '2013-12-23'
AND fri_a <> ''

UNION

SELECT 'fri_n', COUNT(fri_n)
FROM schedule
WHERE week_of = '2013-12-23'
AND fri_n <> ''

UNION

SELECT 'sat', count(sat) 
FROM schedule
WHERE week_of = '2013-12-23'
AND sat <> ''

UNION

SELECT 'sun', COUNT(sun) 
FROM schedule
WHERE week_of = '2013-12-23'
AND sun <> ''

以下是數據示例的一小部分：

ColumnA    ColumnB
mon_m      1
mon_a      5
mon_n      6
tue_m      3
tue_a      6
tue_n      2

我需要使用php訪問這些值，以便可以建立表格。 我想使用變量訪問它們。 例如：

echo $mon_m
echo $mon_a
echo $mon_n

哪里

$mon_m = 1
$mon_a = 5
$mon_n = 6

我已經准備好執行SQL語句，並且需要一些幫助將這些值轉換為php變量。

Answer 1

一旦獲得mysql查詢的結果，就可以通過解壓縮運行它

extract($results);

這將為數組中的每個鍵創建一個變量，因此請確保您的結果作為關聯數組返回。 有關更多詳細信息，請參見http://www.php.net/manual/zh/function.extract.php 。

Answer 2

為什么不使用數組？

$output_array = array(
    "mon_m" => 1,
    "mon_a" => 2,
    "mon_n" => 3
);

然后像這樣輸出它們

echo $output_array['mon_m'];

而且，在這種情況下，使用mysql可以獲得更輕松的結果。

$r = mysql_query("select * from table where columnB=" . $var);
while($row = mysql_fetch_assoc($r)){
    $column = $row['columnA'];
    $output_array[$column] = $row['columnB'];
}

然后，您可以使用它進行各種操作，循環並輸出表，檢查值，鍵等。使用您所建議的內容，跟蹤創建的var並不是一件容易的事，或通常很容易與他們合作。

編輯：：

這是一種更好的方法？ 可能因您的需求而異常復雜，但有注釋建議您使用PDO ...

function getObject($sql){
    $dbCon = new object();
        // building data source name 
        $dsn = 'mysql:host=' . DB_HOST .
               ';dbname='    . DB_NAME .
               ';connect_timeout=15';

        $dbCon->dbh = new PDO($dsn, DB_USER, DB_PASS);

    try {

        $stmt = $dbCon->dbh->prepare($sql);

        $stmt->setFetchMode(PDO::FETCH_OBJ);

        if($stmt->execute()){
                return (array) $stmt->fetchObject();
        } else {
            return false;
        }
    }

    catch(PDOException $e) {  
        $_messages[] = $e->getMessage();  
    }
}

像這樣使用

$my_array = getObject($your_query);

if(!empty($my_array['mon_m'])){
    echo $my_array['mon_m'];
}