將raw_input answer設置為預定義變量

Question

新手在這里。

我想讓Python查看變量（在這種情況下，john，clark和bruce）並吐出那些數組中的字符串，但我沒有運氣弄清楚如何。 這是我正在研究的例子：

names = ("john", "clark", "bruce")

john = ("doe", "13-apr-1985")
clark = ("kent", "11-jan—1987")
bruce = ("wayne", "05-sep-1988")

user = raw_input("What is your name?")
if user in names:
  print "Your last name is: " + ????[0]
  print "Your date of birth is: " + ????[1]
else:
  print "I don’t know you."

問號是我被困的地方。 我不知道如何將兩者聯系在一起。 我希望我的問題不會太混亂。

Answer 1

你可以使用字典：

names = {
    "john": {
        "last_name": "doe",
        "date_of_birth": "13-apr-1985"
    },
}

user = raw_input("What is your name?")
if user in names:
    print "Your last name is: " + names[user]["last_name"]
    print "Your date of birth is: " + names[user]["date_of_birth"]
else:
    print "I don’t know you."

請注意，當多個人具有相同的名字時，此方法不起作用。 在這種情況下，您需要調整數據結構以相應地處理（並且您需要決定當某人填寫"john"時您將顯示哪些結果）。

Answer 2

使用字典將名字映射到您擁有的元組。

names = { "john": (“doe”, “13-apr-1985”),
          "clark": (“kent”, “11-jan—1987”),
          "bruce": (“wayne”, “05-sep-1988”)}

user = raw_input(“What is your name?”)
if user in names.keys():
  print “Your last name is: “ + names[user][0]
  print “Your date of birth is: “ + names[user][1]
else:
  print “I don’t know you.”

為了使這更加pythonic和更容易使用，創建一個嵌套字典：

names = { "john": {"last": “doe”, "birthdate": “13-apr-1985”},
          "clark": {"last": “kent”, "birthdate": “11-jan—1987”},
          "bruce": {"last": “wayne”, "birthdate": “05-sep-1988”}}

user = raw_input(“What is your name?”)
if user in names.keys():
  print “Your last name is: “ + names[user]["last"]
  print “Your date of birth is: “ + names[user]["birthdate"]
else:
  print “I don’t know you.”

作為旁注，您可能希望在輸入時修剪輸入中的任何前導空格。

...
user = raw_input(“What is your name?”)
user = user.strip()
if user in names.keys():
  ...

Answer 3

你應該在這里使用dict ，就像這樣

d = {"john" : ("doe", "13-apr-1985"),
     "clark" : ("kent", "11-jan-1987"),
     "bruce" : ("wayne", "05-sep-1988")}

...
...
if user in d:
    print “Your last name is: “ + d[user][0]
    print “Your date of birth is: “ + d[user][0]
else:
    print “I don’t know you.”