如何忽略正則表達式中的單個字符

Question

如何忽略單引號？

function FixNameForLink($str){
    // Swap out Non "Letters" with a -
    $text = preg_replace('/[^\\pL\d]+/u', '-', $str); 
    // Trim out extra -'s
    $text = trim($text, '-');
    // Convert letters that we have left to the closest ASCII representation
    $text = iconv('utf-8', 'us-ascii//TRANSLIT', $text);
    // Make text lowercase
    $text = strtolower($text);
    // Strip out anything we haven't been able to convert
    $text = preg_replace('/[^-_\w]+/', '', $text);
    return $text;
}

我給我起了個名字，叫Steven's Barbecue （ Steven's Barbecue ，我想將其轉換為正確的鏈接，例如steven-s-barbecue ，但是以某種方式我需要能夠將'轉換為另一個字符，例如_

為了澄清（避免混亂...），鏈接需要為steven_s-barbecue

Answer 1

解決方案是允許在最初的替換中使用引號字符，然后在末尾用_替換。 下面的例子：

<?php
function FixNameForLink($str){
    // Swap out Non "Letters" with a -
    $text = preg_replace('/[^\pL\d\']+/u', '-', $str);
    // Trim out extra -'s
    $text = trim($text, '-');
    // Convert letters that we have left to the closest ASCII representation
    $text = iconv('utf-8', 'us-ascii//TRANSLIT', $text);
    // Make text lowercase
    $text = strtolower($text);
    // ' has been valid until now... swap it for an _
    $text = str_replace('\'', '_', $text);
    // Strip out anything we haven't been able to convert
    $text = preg_replace('/[^-_\w]+/', '', $text);
    return $text;
}

var_dump(FixNameForLink("Steven's Barbecue")); // steven_s-barbecue

Answer 2

運行str_replace嗎？

$text = str_replace("'", '_', $str);
$text = preg_replace('/[^_\\pL\d]+/u', '-', $text); 

為了安全起見，您也可以在所有功能都運行到最終產品之后運行urlencode() ，因為您嘗試使用破折號而不是%20作為空格