[英]MySQL select column which is a value in another column
我的sql表是這樣的:
+----+------------+--------+---------------+---------------+-------------+----------+-------------+---------------------+
| id | msisdn | status | reason | CallRejection | Unavailable | NoAnswer | NetworkBusy | autotimestamp |
+----+------------+--------+---------------+---------------+-------------+----------+-------------+---------------------+
| 1 | 9999999901 | Failed | NoAnswer | 1 | 2 | 2 | 4 | 2013-12-19 15:46:50 |
| 2 | 9999999902 | Failed | NetworkBusy | 4 | 2 | 3 | 2 | 2013-12-19 13:07:42 |
| 3 | 9999999903 | Failed | CallRejection | 6 | 6 | 6 | 5 | 2013-12-19 13:07:53 |
| 4 | 9999999904 | Failed | Unavailable | 2 | 4 | 2 | 0 | 2013-12-19 13:08:03 |
| 5 | 9999999905 | Failed | Misc | 6 | 2 | 6 | 2 | 2013-12-19 13:07:01 |
| 6 | 9999999906 | Failed | NoAnswer | 1 | 3 | 1 | 6 | 2013-12-19 13:07:24 |
| 7 | 9999999907 | Failed | NetworkBusy | 6 | 6 | 2 | 3 | 2013-12-19 13:07:42 |
| 8 | 9999999908 | Failed | CallRejection | 8 | 3 | 3 | 0 | 2013-12-19 13:07:53 |
| 9 | 9999999909 | Failed | Unavailable | 3 | 8 | 5 | 6 | 2013-12-19 13:08:03 |
| 10 | 9999999910 | Failed | Misc | 8 | 4 | 0 | 4 | 2013-12-19 13:07:01 |
+----+------------+--------+---------------+---------------+-------------+----------+-------------+---------------------+
我想根據每行的reason
列的值提取每個原因的值。 例如:
row 1
應該給出2
作為結果,因為reason
列具有noanswer
,因此應該返回該特定列的值,即noanswer
。
實際上,我必須在將返回的值與常量進行比較后選擇多行。 我可以通過以下方法執行此操作:
select @col := reason from msisdn_table where id=1;
SET @a = concat('select ', @col, ' from msisdn_table where id=1');
PREPARE STMT FROM @a;
EXECUTE STMT;
DEALLOCATE PREPARE STMT;
但這不是一個非常有前途的解決方案,因為它只用於一行,我將不得不使用for循環以獲得1000行的塊,這將不是非常有效。 什么是更有效的方式?
嘗試這個:
SELECT id,
reason
CASE
WHEN reason = 'NoAnswer' THEN NoAnswer
WHEN reason = 'NetworkBusy' THEN NetworkBusy
END AS value
FROM table1
它應該給你一個像這樣的輸出:
+----+------------+----------+
| id | reason | value |
+----+------------+----------+
| 1 | NoAnswer | 2 |
+----+------------+----------+
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