[英]Not unique table/alias: 'request
我的應用程序中有以下查詢,
$que="SELECT DISTINCT prescription.commodity_name, prescription.dosage, prescription.duration, prescription.prescription_id, prescription.remarks, prescription.paid, employee.f_name, prescription.quantity_requested, employee.s_name, employee.other_name, prescription.doctor_id, request.strength, stock.unit_per_pack, stock.selling_price, stock.buying_price
FROM prescription
INNER JOIN request ON prescription.medname = request.commodity_name
INNER JOIN stock ON stock.stock_id = request.stock_id
INNER JOIN request ON request.request_id = transaction.transaction_id
INNER JOIN employee ON employee.employee_id = prescription.doctor_id
INNER JOIN visit ON prescription.visit_id = visit.visit_id
WHERE prescription.visit_id = '".$id."'";
運行腳本文件時,出現以下數據錯誤:不是唯一的表/別名:'request
我該如何解決這個問題?或者我做錯了什么?
您在request
執行兩個聯接,這意味着,例如,當您SELECT request.strength
不知道要使用哪個表。
考慮添加別名:
SELECT DISTINCT prescription.commodity_name, prescription.dosage, prescription.duration, prescription.prescription_id, prescription.remarks, prescription.paid, employee.f_name, prescription.quantity_requested, employee.s_name, employee.other_name, prescription.doctor_id,
r1.strength, -- Switched to use r1 alias
stock.unit_per_pack, stock.selling_price, stock.buying_price
FROM prescription
INNER JOIN request r1 ON prescription.medname = r1.commodity_name -- Using alias r1
INNER JOIN stock ON stock.stock_id = r1.stock_id
INNER JOIN request r2 ON r2.request_id = transaction.transaction_id -- Using alias r2
INNER JOIN employee ON employee.employee_id = prescription.doctor_id
INNER JOIN visit ON prescription.visit_id = visit.visit_id
WHERE prescription.visit_id = '".$id."'"
請注意,您可能需要調整上面使用的別名。
您在兩個聯接中使用了相同的別名“ request”。 您需要為其指定一個唯一的別名,例如:
SELECT DISTINCT * FROM prescription a
INNER JOIN request b ON a.medname = b.commodity_name
INNER JOIN stock c ON c.stock_id = b.stock_id
INNER JOIN request d ...
另外,您的查詢中有錯誤嗎? 您似乎正在嘗試聯接到稱為transaction
的表,但未在聯接中定義它:
INNER JOIN request ON request.request_id = transaction.transaction_id
該請求表實際上應該是事務嗎?:
INNER JOIN transaction ON request.request_id = transaction.transaction_id
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