C ++ WSAsend數據包的奇怪十六進制轉儲

Question

http://prntscr.com/2ctnoz

我正在掛鈎WSAsend函數並轉儲數據包。 ASCII轉儲有效，但HEX轉儲有時會顯示你可以在屏幕上看到的東西（FFFFFFDD），任何想法為什么？

碼：

int WINAPI myWSASend(SOCKET s, LPWSABUF lpBuffers, DWORD dwBufferCount, LPDWORD lpNumberOfBytesSent, DWORD dwFlags, LPWSAOVERLAPPED lpOverlapped, LPWSAOVERLAPPED_COMPLETION_ROUTINE lpCompletionRoutine)
{   
    //Packet Log
    if (bLogPacketS == TRUE)
    {
        for (unsigned int i = 0; i < lpBuffers->len; i = i + 8)
        {
            printf("%02X %02X %02X %02X %02X %02X %02X %02X\t\t%c %c %c %c %c %c %c %c\n",
                  (unsigned int)lpBuffers->buf[i], (unsigned int)lpBuffers->buf[i+1], (unsigned int)lpBuffers->buf[i+2],
                  (unsigned int)lpBuffers->buf[i+3], (unsigned int)lpBuffers->buf[i+4], (unsigned int)lpBuffers->buf[i+5],
                  (unsigned int)lpBuffers->buf[i+6], (unsigned int)lpBuffers->buf[i+7],
                  (drawable((unsigned int)lpBuffers->buf[i])) ? (unsigned int)lpBuffers->buf[i] : '.',
                  (drawable((unsigned int)lpBuffers->buf[i+1])) ? (unsigned int)lpBuffers->buf[i+1] : '.',
                  (drawable((unsigned int)lpBuffers->buf[i+2])) ? (unsigned int)lpBuffers->buf[i+2] : '.',
                  (drawable((unsigned int)lpBuffers->buf[i+3])) ? (unsigned int)lpBuffers->buf[i+3] : '.',
                  (drawable((unsigned int)lpBuffers->buf[i+4])) ? (unsigned int)lpBuffers->buf[i+4] : '.',
                  (drawable((unsigned int)lpBuffers->buf[i+5])) ? (unsigned int)lpBuffers->buf[i+5] : '.',
                  (drawable((unsigned int)lpBuffers->buf[i+6])) ? (unsigned int)lpBuffers->buf[i+6] : '.',
                  (drawable((unsigned int)lpBuffers->buf[i+7])) ? (unsigned int)lpBuffers->buf[i+7] : '.');
        }
        printf("\n\n");
    }
    return (oWSASend)(s, lpBuffers, dwBufferCount, lpNumberOfBytesSent, dwFlags, lpOverlapped, lpCompletionRoutine);
}

bool drawable(unsigned int value)
{
    if (value > 32 && value < 127)
        return true;
    else
        return false;
}

Answer 1

你投的錯了。

您只想更改簽名，但您也將每個字節擴展為一個四字節的字。 在存在有符號到無符號的轉換（以及由此產生的負值環繞）的情況下，這會導致極高的值。

---

lpBuffers->buf[i]每個“元素”都是一個char ，但是你要轉換為unsigned int 。 如果您的char在您的系統上簽名，則0xDD不在該類型范圍的頂部，因此它將回繞到-35 。 然后將其轉換為unsigned int導致0xFFFFFFDD 。

printf說明符%02X不會截斷它。

假設您希望將所有字節解釋為unsigned ，以獲得完整的0x00 → 0xFF范圍。 就個人而言，我將轉換為unsigned char （而不是unsigned int ），其值為0xDD為221 。

在下面的代碼中，我還對您的循環條件進行了安全調整。

for (unsigned int i = 0; i < lpBuffers->len-8; i = i + 8)
//                                         ^^
{
    printf(
        "%02X %02X %02X %02X %02X %02X %02X %02X"
          "\t\t%c %c %c %c %c %c %c %c\n",

        static_cast<unsigned char>(lpBuffers->buf[i]),
        static_cast<unsigned char>(lpBuffers->buf[i+1]),
        static_cast<unsigned char>(lpBuffers->buf[i+2]),
        static_cast<unsigned char>(lpBuffers->buf[i+3]),
        static_cast<unsigned char>(lpBuffers->buf[i+4]),
        static_cast<unsigned char>(lpBuffers->buf[i+5]),
        static_cast<unsigned char>(lpBuffers->buf[i+6]),
        static_cast<unsigned char>(lpBuffers->buf[i+7]),
        (drawable(lpBuffers->buf[i]))   ? static_cast<unsigned char>(lpBuffers->buf[i])   : '.',
        (drawable(lpBuffers->buf[i+1])) ? static_cast<unsigned char>(lpBuffers->buf[i+1]) : '.',
        (drawable(lpBuffers->buf[i+2])) ? static_cast<unsigned char>(lpBuffers->buf[i+2]) : '.',
        (drawable(lpBuffers->buf[i+3])) ? static_cast<unsigned char>(lpBuffers->buf[i+3]) : '.',
        (drawable(lpBuffers->buf[i+4])) ? static_cast<unsigned char>(lpBuffers->buf[i+4]) : '.',
        (drawable(lpBuffers->buf[i+5])) ? static_cast<unsigned char>(lpBuffers->buf[i+5]) : '.',
        (drawable(lpBuffers->buf[i+6])) ? static_cast<unsigned char>(lpBuffers->buf[i+6]) : '.',
        (drawable(lpBuffers->buf[i+7])) ? static_cast<unsigned char>(lpBuffers->buf[i+7]) : '.'
    );
}