以分鍾，小時為單位的兩個日期之間的差異javascript

Question

我想找到兩個日期之間的差異。 我試過這段代碼，但它給了我錯誤的值。 我想獲得兩個日期之間的總分鍾數，所以我將小時轉換為分鍾並添加到分鍾。

var hourDiff = timeEnd - timeStart;
var diffHrs = Math.round((hourDiff % 86400000) / 3600000);
var diffMins = Math.round(((hourDiff % 86400000) % 3600000) / 60000);
diffMins = diffMins + (diffHrs * 60);

這里timeEnd是Mon Jan 01 2007 11:30:00 GMT+0530 (India Standard Time) timeEnd Mon Jan 01 2007 11:30:00 GMT+0530 (India Standard Time) ，

和timeStart是Mon Jan 01 2007 11:00:00 GMT+0530 (India Standard Time) 。

在這里，如果小時差異我得到1 ，它應該是0和分鍾我得到30是正確的。 但是 hours 應該是0 。 我在這里做錯了嗎？

Answer 1

試試這個代碼（使用 ms 作為初始單位）

var timeStart = new Date("Mon Jan 01 2007 11:00:00 GMT+0530").getTime();
var timeEnd = new Date("Mon Jan 01 2007 11:30:00 GMT+0530").getTime();
var hourDiff = timeEnd - timeStart; //in ms
var secDiff = hourDiff / 1000; //in s
var minDiff = hourDiff / 60 / 1000; //in minutes
var hDiff = hourDiff / 3600 / 1000; //in hours
var humanReadable = {};
humanReadable.hours = Math.floor(hDiff);
humanReadable.minutes = minDiff - 60 * humanReadable.hours;
console.log(humanReadable); //{hours: 0, minutes: 30}

JSFiddle： http : //jsfiddle.net/n2WgW/

Answer 2

嘗試：

var diffHrs = Math.floor((hourDiff % 86400000) / 3600000);

Math.round將0.5小時的差異四舍五入為1 。 您只想在小時變量中獲得“完整”小時數，是否使用Math.floor()從變量中刪除所有分鍾數

Answer 3

試試這個：

var startDate = new Date('Jan 01 2007 11:00:00');
var endDate = new Date('Jan 01 2007 11:30:00');
var starthour = parseInt(startDate.getHours());
var endhour = parseInt(endDate.getHours());

if(starthour>endhour){
    alert('Hours diff:' + parseInt(starthour-endhour));
}
else{
    alert('Hours diff:' + parseInt(endhour-starthour));
}

這是工作小提琴。

Answer 4

如果您確信差異將小於 24 小時，則以下方法有效。

var timeStart= new Date('2015-01-01 03:45:45.890');
var timeEnd = new Date('2015-01-01 05:12:34.567');
var timeDiff = new Date(timeEnd.getTime() - timeStart.getTime());
var humanTime = timeDiff.toISOString().substring(11, 23);
var diffHours = timeDiff.toISOString().substring(11, 12);

humanTime 是 01:26:48.677，diffHours 是 01

Answer 5

你可以試試這個：-

function diff_hours(dt2, dt1) 
 {

  var diff =(dt2.getTime() - dt1.getTime()) / 1000;
  diff /= (60 * 60);         // For Hours
  //diff /= (60);          For Minutes
  return Math.abs(Math.round(diff));

 }

dt1 = new Date(2014,10,2);
dt2 = new Date(2014,10,3);
console.log(diff_hours(dt1, dt2));            // you will get '24' hours


dt1 = new Date("October 13, 2014 08:11:00");
dt2 = new Date("October 13, 2014 11:13:00");
console.log(diff_hours(dt1, dt2));           // you will get '3' hours

Answer 6

var timeDiff = function (date1, date2) {
        var a = new Date(date1).getTime(),
            b = new Date(date2).getTime(),
            diff = {};

        diff.milliseconds = a > b ? a % b : b % a;
        diff.seconds = diff.milliseconds / 1000;
        diff.minutes = diff.seconds / 60;
        diff.hours = diff.minutes / 60;
        diff.days = diff.hours / 24;
        diff.weeks = diff.days / 7;

        return diff;
    }

Answer 7

您可以使用以下方法獲得以小時、分鍾和秒為單位的時差，例如倒計時：

var diff = EndedTime - StartedTime;
var hours   = Math.floor(diff / 3.6e6);
var minutes = Math.floor((diff % 3.6e6) / 6e4);
var seconds = Math.floor((diff % 6e4) / 1000);
var duration = hours+":"+minutes+":"+seconds;

希望這有幫助。 謝謝

Answer 8

您可以以小時和分鍾格式獲得時差，如下所示

const startTime = new Date(event.startTime);
const endTime = new Date(event.endTime);
const diff = endTime.getTime() - startTime.getTime();
const hrDiff = diff / 3600 / 1000; // 1.555555
const totalHours = parseFloat((hrDiff).toFixed(2)); // 1.5