在HTML中打印php變量

Question

我一直在努力使自己陷入困境，試圖弄清楚如何將一些PHP變量打印到一些HTML中。 我似乎無法正確理解單引號或雙引號。

我正在從500px API中提取圖像，並且希望將其渲染到引導輪播中。 我要使用的變量是$photo->name （我將其放在下面的標題標簽和$photo->url ，而不是placehold.it url中。我嘗試的所有操作都給了我一個解析錯誤：語法錯誤，但是意外的T_VARIABLE錯誤 。

有人可以幫忙嗎？

<?php           
      $i = 0;      
      $len = count($obj);
      foreach ($obj->photos as $photo){

        if ($i==0) {
          print '<div class="item active">
                    <div class="fill" style="background-image:url('http://placehold.it/1900x1080&amp;text=Slide One');">
                    </div>
                  <div class="carousel-caption">
                    <h1>$photo->name</h1>
                  </div>
                  </div>';
        } else {
          print "hello 2";
        }
        $i++;
      }
  ?>

Answer 1

有多種使用“ echo”的方法，包括：

$world = "world";

#If you wrap your statement in double-quotes, then:
echo "Hello $world, nice to meet you.";

#If you wrap your echo statement in single-quotes, then:
echo 'Hello '.$world.', nice to meet you.';

因此，您可以考慮將代碼更改為：

<?php 

  $url = 'http://placehold.it/1900x1080&amp;text=Slide One';
  $i = 0;      
  $len = count($obj);

  foreach ($obj->photos as $photo){

    if ($i==0) {

      print '<div class="item active">
                <div class="fill" style="background-image:url(\''.$url.'\');">
                </div>
              <div class="carousel-caption">
                <h1>'.$photo->name.'</h1>
              </div>
              </div>';

    } else {

      print "hello 2";

    }

    $i++;

  }

？>

Answer 2

嘗試這個

 <?php           
          $i = 0;      
          $len = count($obj);
          foreach ($obj->photos as $photo){

            if ($i==0) {
              print '<div class="item active">
                        <div class="fill" style="background-image:url(\'http://placehold.it/1900x1080&amp;text=Slide One\');">
                        </div>
                      <div class="carousel-caption">
                        <h1>'.$photo->name.'</h1>
                      </div>
                      </div>';
            } else {
              print "hello 2";
            }
            $i++;
          }
      ?>

Answer 3

..."background-image:url(\'http://placehold.it/1900x1080&text=Slide One\')"...

使用\\逃逸

Answer 4

使用echo並在雙引號之間粘貼html5代碼。 例：

echo "<div id='mydiv'>$phpvar</div>";

或用點將var連接起來：

    echo "<div id='mydiv'>".$phpvar."</div>";

有時錯誤取決於單引號或雙引號。

---

玩得開心！ （：

Answer 5

您遇到字符串轉義的問題，請注意以下示例：

$variable = 'my string';

echo $variable ; // my string
echo '$variable '; // $variable
echo "$variable "; // my string

$variable = 'my st'ring'; // ERROR
$variable = 'my st\'ring'; // escaped properly

echo $variable ; // my st'ring
echo '$variable '; // $variable
echo "$variable "; // my st'ring

Answer 6

<?php           
      $i = 0;      
      $len = count($obj);
      foreach ($obj->photos as $photo){

        if ($i==0) {
          print "<div class='item active'>
                    <div class='fill' style='background-image:url(\"http://placehold.it/1900x1080&amp;text=Slide One\");'>
                    </div>
                  <div class='carousel-caption'>
                    <h1>$photo->name</h1>
                  </div>
                  </div>";
        } else {
          print "hello 2";
        }
        $i++;
      }
?>

Answer 7

如果要添加變量以進行打印或回顯，則必須關閉引號，並在起點和終點處添加一個點。 例如：

<?php
     $and = "and";
     echo "Hello ".$and." how are you?"; //prints Hello and how are you
?>

編輯：不是我沒有注意到您在url()之間加了引號。 PHP認為字符串在那里停止。 如果希望后面的下一個字母成為字符串的一部分，則必須在其前面添加一個左斜杠： \\ 。 例如：

<?php
    echo "My teacher said "You are not listening!"."; // Even SO's editor thinks that "You are not listening!" isn't a part of the string and adds a color. It will return an erro.
    // the right way is:
    echo "My teacher said \"You are not listening!\"."; // Here you can see that the editor doesn't adds color to whatever in the quotes because it know that is is a part of the string. It prints My teacher said "You are not listening!".
?>

在您的情況下：

<?php           
      $i = 0;      
      $len = count($obj);
      foreach ($obj->photos as $photo){

        if ($i==0) {
          print '<div class="item active">
                    <div class="fill" style="background-image:url(\'http://placehold.it/1900x1080&amp;text=Slide One\');">
                    </div>
                  <div class="carousel-caption">
                    <h1>'.$photo->name.'</h1>
                  </div>
                  </div>';
        } else {
          print "hello 2";
        }
        $i++;
      }
  ?>