將當前的user_id分配為其他表中的外部值

Question

我有以下表格用戶（ID，名稱，電子郵件），文章（ID，user_id，標題，正文）。 我似乎無法用登錄的user_id填充articles表中的user_id。 這是我的代碼。
//文章控制器

    public function add() {
    if ($this->request->is('post')) {
    $this->Article->create();
    $this->request->data['Article']['user_id'] = $user_id;
    if ($this->Article->save($this->request->data)) {
    $this->Session->setFlash(__('The article has been saved.'));
    return $this->redirect(array('action' => 'index'));
    } else {
    $this->Session->setFlash(__('The article could not be saved. Please, try again.'));
    }
    }
    $users = $this->Article->User->find('list');
    $this->set(compact('users'));
    }

上面的方法為文章中的user_id返回空值

我也嘗試從視圖中檢索：

    echo $this->Form->hidden('user_id', arrray('value' => $userAuth['id']));

我收到以下錯誤語法錯誤，意外的'=>'（T_DOUBLE_ARROW）

Answer 1

echo $this->Form->hidden('user_id', arrray('value' => $userAuth['id']));

應該，

echo $this->Form->hidden('user_id', array('value' => $userAuth['id']));

錯別字（R的3倍）。

Answer 2

嘗試這個：

public function add() {
    if ($this->request->is('post')) {
       $this->Article->create();
       if ($this->Article->save($this->request->data)) {
          $this->Session->setFlash(__('The article has been saved.'));
          return $this->redirect(array('action' => 'index'));
       } else {
          $this->Session->setFlash(__('The article could not be saved. Please, try again.'));
    }
    else{
        $this->set('user_id', $userAuth['id']);
        $users = $this->Article->User->find('list');
        $this->set(compact('users'));
    }
}

在視圖中

echo $this->Form->hidden('Article.user_id', arrray('value' => $user_id));

但是我不知道您在哪里設置$userAuth ，請確保在獲取變量值之前分配該變量