如何在向量大小上循環C ++

Question

我是C ++編程的新手，並且有一個關於Vector大小和for循環的問題。

假設我的Vector大小為3，其中包含值：

x = [Susan 13, Female, Chicago Illinois] //this will be the comparison point
y = [Sally 18, Female, Tokyo Japan]     
z = [Rowland 2, Male, Arizona California] //y & z will be compared to x
+...other vectors depending on how many the user inputs

我想創建一個for循環，通過將y＆z與x進行比較來生成每個年齡。 所以我希望它像

x[0] - y[0] --> 5  //difference of the ages
x[0] - z[0] --> 11

到目前為止，我有這個：

vector<string> age, gender, location;

void ageDiff(vector<string> a, vector<string> g, vector<string> l){
     //i want to start calculating the age differences but i'm not sure how to loop depending on how many data the user inputs
}

int main(){
    int n;
    std::cout << "How many data will you input? ";
    std::cin >> n;

    for (a=0;a<n;a++){
        std::cout << "Please enter the data for person #" << a;
        std::cin >> a;
        std::cin >> b;
        std::cin >> c;
        age.push_back(a);
        gender.push_back(b);
        location.push_back(c);

    for (a=0;a<(age.size()-1);a++){
        ageDiff(age, gender, location)
    }

Answer 1

您的示例不是如何使用C ++。 創建一個包含int年齡，布爾或枚舉性別以及字符串位置作為私有成員的類/結構。 這些成員應該可以通過int getAge()和void setAge(int newAge)類的方法進行訪問。 這將大大簡化您的原始任務。 創建人的矢量people和循環遍歷它：

for (size_type i = 0; i < people.size(); i++)
  for (size_type j = i + 1; j < people.size(); j++)
     std::cout << "age difference between "  << i << " and " << j << " is " 
       << std::abs(people[i].getAge() - people[j].getAge()) << "." << std::endl;