如何使用Php中的Select Option在Grid視圖中獲取數據

Question

選擇列表框項目后，我想顯示數據。 以前，在Grid View中所有數據都將存在。 如果用戶選擇了一個選項，則僅應顯示該選項數據。 如何在PHP中做到這一點。 這是我的代碼

 <td width="5%" align="right"><b>School<b></td><td width="1%"><b>:</b></td><td width="5%" align="left">
<select name="school_id" id="school_id" class="list_box">
<option value="">Select School</option>
<?php
$school_sql=mysql_query("select * from tbl_school");
while($school=mysql_fetch_array($school_sql))
{
?>
<option value="<?php echo $school['school_id'];?>" <?php if(isset($workshop_fetch['school_id']) && ($workshop_fetch['school_id']==$school['school_id'])) { echo "selected='selected'"; } ?> ><?php echo $school['school_name'];?></option>
<?php } ?>
</select>
 </td>
 </tr> 

  <tr class="table_txt2">
    <td width="7%">S.No</td>
    <td width="20%">School</td>
    <td width="10%">Payment Details</td>
    <td width="20%">Payment Date</td>
    <td width="13%">Amount</td>
    <td width="10%">Due Date</td>
    <td width="10%">Paid Date</td>
    <td width="10%">Is Paid</td>
  </tr>
  <?php
$slno=0;
$payment_sql=mysql_query("select * from tbl_school_payments");

while($result=mysql_fetch_array($payment_sql))
{
$slno++;

?>
<tr <?php if($slno%2==1) echo "class='table_txt3'"; else echo "class='table_txt4'"; ?> id="row_<?php echo $result['payment_id']; ?>">
<td ><?php echo $slno;?></td>
<td >
<?php
$school_sql=mysql_query("select * from tbl_school where school_id='$result[school_id]'");
$school=mysql_fetch_array($school_sql);
 echo ucwords($school['school_name']);
 ?>
</td>



//Here code for display data 
    <td ><?php echo $result['payment_details'];?></td>
    <td ><?php echo $result['payment_date'];?></td>
    <td ><?php echo $result['amount_paid'];?></td>
    <td ><?php echo $result['due_date'];?></td>
    <td ><?php echo $result['paid_date'];?></td>
    <td ><?php echo $result['is_paid'];?></td>

      <?php } ?>
      </table>

Answer 1

<td width="5%" align="right"><b>School<b></td><td width="1%"><b>:</b></td><td width="5%" align="left">
<select name="school_id" id="school_id" class="list_box">
<option value="">Select School</option>
<?php
$school_sql=mysql_query("select * from tbl_school");
while($school=mysql_fetch_array($school_sql))
{
?>
<option value="<?php echo $school['school_id'];?>" <?php if(isset($workshop_fetch['school_id']) && ($workshop_fetch['school_id']==$school['school_id'])) { echo "selected='selected'"; } ?> ><?php echo $school['school_name'];?></option>
<?php } ?>
</select>
 </td>
 </tr> 

  <tr class="table_txt2">
    <td width="7%">S.No</td>
    <td width="20%">School</td>
    <td width="10%">Payment Details</td>
    <td width="20%">Payment Date</td>
    <td width="13%">Amount</td>
    <td width="10%">Due Date</td>
    <td width="10%">Paid Date</td>
    <td width="10%">Is Paid</td>
  </tr>
  <?php
$slno=0;
$payment_sql=mysql_query("select * from tbl_school_payments");
while($result=mysql_fetch_array($payment_sql))
{
$slno++;

?>
<tr <?php if($slno%2==1) echo "class='table_txt3'"; else echo "class='table_txt4'"; ?> id="row_<?php echo $result['payment_id']; ?>">
<td ><?php echo $slno;?></td>
<td >
<?php
/*This IF block added
===================== */
if(isset($_GET['id']))
{

    $query = "select * from tbl_school where school_id=".mysql_real_escape_string($_GET['id']);
}
else
{
    $query = "select * from tbl_school where school_id='$result[school_id]'";
}
$school_sql=mysql_query($query);
$school=mysql_fetch_array($school_sql);
 echo ucwords($school['school_name']);
 ?>
</td>



//Here code for display data 
    <td ><?php echo $result['payment_details'];?></td>
    <td ><?php echo $result['payment_date'];?></td>
    <td ><?php echo $result['amount_paid'];?></td>
    <td ><?php echo $result['due_date'];?></td>
    <td ><?php echo $result['paid_date'];?></td>
    <td ><?php echo $result['is_paid'];?></td>

<?php } ?>
</table>

添加了腳本標簽

<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script>
<script type="text/javascript">

jQuery(document).ready(function($) {
      jQuery('#school_id').change(function(e){

          selected = jQuery('#school_id').val();
          window.location = window.location.pathname + '?id=' + selected;

      });
});

基本上發生的是，當您選擇school_id ，jQuery change()函數將觸發並將所選的school_id附加到當前URL並轉到該URL。 現在，URL具有一個id = school_id值，PHP在執行查詢之前會對其進行檢查。 如果有一個，它將在其select語句中使用該值。

這是您所需要的嗎？