Android：將html文件上傳到http服務器

Question

我目前正在嘗試使用Android將HTML文件上傳到我的燈服務器。 我真的不知道如何獲取文件上傳到服務器。 我正在做的是：以編程方式編寫HTML文件，然后將其上傳到Web服務器。
我知道有可能

我已經開始寫文件了。 我的服務器上也有一個上傳腳本：

<?php
$target_path  = "./";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
 echo "The file ".  basename( $_FILES['uploadedfile']['name']).
 " has been uploaded";
} else{
 echo "There was an error uploading the file, please try again!";
}
?>

我已經閱讀了所有有關如何執行此操作的教程，但我根本不了解。

Answer 1

您可以將其用作android代碼：

public int uploadFile(String sourceFileUri) {

    HttpURLConnection conn = null;
    DataOutputStream dos = null;
    String lineEnd = "\r\n";
    String twoHyphens = "--";
    String boundary = "*****";
    int bytesRead, bytesAvailable, bufferSize;
    byte[] buffer;
    int maxBufferSize = 1 * 1024 * 1024;
    File sourceFile = new File(sourceFileUri);

    if (!sourceFile.isFile()) {
        Log.e("uploadFile", "Source File not exist :" + uploadFilePath + "" + uploadFileName);
        return 0;
    }
    else
    {
        try {
            // open a URL connection to the Servlet
            FileInputStream fileInputStream = new FileInputStream(sourceFile);
            URL url = new URL(upLoadServerUri);

            // Open a HTTP  connection to  the URL
            conn = (HttpURLConnection) url.openConnection();
            conn.setDoInput(true); // Allow Inputs
            conn.setDoOutput(true); // Allow Outputs
            conn.setUseCaches(false); // Don't use a Cached Copy
            conn.setRequestMethod("POST");
            conn.setRequestProperty("Connection", "Keep-Alive");
            conn.setRequestProperty("ENCTYPE", "multipart/form-data");
            conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
            conn.setRequestProperty("uploadedfile", sourceFileUri);

            dos = new DataOutputStream(conn.getOutputStream());

            dos.writeBytes(twoHyphens + boundary + lineEnd);
            dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + sourceFileUri + "\"" + lineEnd);
            dos.writeBytes(lineEnd);


            // create a buffer of  maximum size
            bytesAvailable = fileInputStream.available();

            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            buffer = new byte[bufferSize];

            // read file and write it into form...
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0) {
                dos.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            }

            // send multipart form data necesssary after file data...
            dos.writeBytes(lineEnd);
            dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            // Responses from the server (code and message)
            serverResponseCode = conn.getResponseCode();
            String serverResponseMessage = conn.getResponseMessage();

            Log.i("uploadFile", "HTTP Response is : "+ serverResponseMessage + ": " + serverResponseCode);

            if(serverResponseCode == 200){
                Log.e("uploadFile", "File Uploaded.");
                // Congrats!
            }

            //close the streams //
            fileInputStream.close();
            dos.flush();
            dos.close();

        } catch (Exception e) {
            Log.e("Upload file to server Exception", "Exception : " + e.getMessage(), e);
        }
        return serverResponseCode;

    } // End else block
}