[英]Group By First Query in MySql
我需要將以下(訪問中的sql)轉換為mysql。 它是第一個查詢的組,但是obv mysql無法處理第一個或最后一個。
SELECT First([20121202].Date) AS FirstOfDate, First([20121202].Time) AS FirstOfTime, [20121202].HomeMatchingId, [20121202].AwayMatchingId, [20121202].RunningStatus
FROM 20121202
GROUP BY [20121202].HomeMatchingId, [20121202].AwayMatchingId, [20121202].RunningStatus
HAVING ((([20121202].RunningStatus)=1))
基本上我是在比賽(hometeam v awayteam)進場的時間之后(runningstatus = 1)
提前致謝
不知道日期是什么,但使用常規聚合怎么樣?
SELECT
MIN(`Date`) AS `FirstOfDate`,
MIN(`Time`) AS `FirstOfTime`,
`HomeMatchingId`,
`AwayMatchingId`,
`RunningStatus`
FROM `20121202`
GROUP BY
`HomeMatchingId`,
`AwayMatchingId`,
`RunningStatus`
HAVING
`RunningStatus`=1
我認為first
的目的是獲得最早的日期。 如果每個日期最多有一行,那么您可以:
SELECT t.Date AS FirstOfDate, t.Time AS FirstOfTime,
t.HomeMatchingId, t.AwayMatchingId, t.RunningStatus
FROM `20121202` t join
(select HomeMatchingId, AwayMatchingId, min(date) as mindate
from `20121202`
WHERE RunningStatus = 1;
group by HomeMatchingId, AwayMatchingId
) tmin
on t.date = tmin.date and t.HomeMatchingId = tmin.HomeMatchingId and
tmin.AwayMatchingId and t.AwayMatchingId and
WHERE RunningStatus = 1;
我將RunningStatus
上的條件移動到where
子句,因為這樣更有效。
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