[英]get a count of each value from every column in a table SQL Server
所以我查了一下,這個問題非常相似,但它缺少一個關鍵部分: SQL Server計數表的每列中不同值的數量
所以在那個問題中,他們希望每列都有不同的計數。 我想要做的是獲取表中每列的每個不同值的計數(我正在為特定數據庫中的所有表執行此操作,這就是為什么我要嘗試自動化這個盡可能)。 目前我的代碼看起來像我必須為每列運行:
select mycol1, COUNT(*) as [Count]
from mytable
group by mycol1
order by [Count] desc
理想情況下,我的輸出看起來像這樣:
ColumnName1 Count
val1 24457620
val2 17958530
val3 13350
ColumnName2 Count
val1 24457620
val2 17958530
val3 13350
val4 12
等等表格中的所有列
下面的答案(由@beargle提供)來自上一個問題非常接近我想要做的事情,但我似乎無法找到一種方法讓它為我想要做的工作所以我會感謝任何幫助。
DECLARE @Table SYSNAME = 'TableName';
-- REVERSE and STUFF used to remove trailing UNION in string
SELECT REVERSE(STUFF(REVERSE((SELECT 'SELECT ''' + name
+ ''' AS [Column], COUNT(DISTINCT('
+ QUOTENAME(name) + ')) AS [Count] FROM '
+ QUOTENAME(@Table) + ' UNION '
-- get column name from sys.columns
FROM sys.columns
WHERE object_id = Object_id(@Table)
-- concatenate result strings with FOR XML PATH
FOR XML PATH (''))), 1, 7, ';'));
你可以使用:
DECLARE @Table SYSNAME = 'TableName';
DECLARE @SQL NVARCHAR(MAX) = ''
SELECT @SQL = STUFF((SELECT ' UNION SELECT ''' + name
+ ''' AS [Column], '
+ 'CAST(' + QUOTENAME(Name)
+ ' AS NVARCHAR(MAX)) AS [ColumnValue], COUNT(*) AS [Count] FROM '
+ QUOTENAME(@Table) + ' GROUP BY ' + QUOTENAME(Name)
FROM sys.columns
WHERE object_id = Object_id(@Table)
-- concatenate result strings with FOR XML PATH
FOR XML PATH ('')), 1, 7, '');
EXECUTE sp_executesql @SQL;
哪個會產生SQL如下表所示,有兩列(Column1和Column2)
SELECT 'Column1' AS [Column],
CAST([Column1] AS NVARCHAR(MAX)) AS [ColumnValue],
COUNT(*) AS [Count]
FROM [TableName]
GROUP BY [Column1]
UNION
SELECT 'Column2' AS [Column],
CAST([Column2] AS NVARCHAR(MAX)) AS [ColumnValue],
COUNT(*) AS [Count]
FROM [TableName]
GROUP BY [Column2]
編輯
如果您想為每列添加新的結果集,請使用:
DECLARE @Table SYSNAME = 'TableName';
DECLARE @SQL NVARCHAR(MAX) = '';
SELECT @SQL = (SELECT ' SELECT ' + QUOTENAME(Name)
+ ', COUNT(*) AS [Count] FROM '
+ QUOTENAME(@Table) + ' GROUP BY ' + QUOTENAME(Name) + ';'
FROM sys.columns
WHERE object_id = Object_id(@Table)
-- concatenate result strings with FOR XML PATH
FOR XML PATH (''));
EXECUTE sp_executesql @SQL;
哪個會產生SQL Like:
SELECT [Column1],
COUNT(*) AS [Count]
FROM [callsupplier]
GROUP BY [Column1];
SELECT [Column2],
COUNT(*) AS [Count]
FROM [callsupplier]
GROUP BY [Column2];
我以為我會在等待備份還原的時候捅這個
希望這能滿足您的需求
create Table #Temp
(tableName varchar(100),
columnName varchar(100),
value varchar(1000),
distinctItems int)
Declare @tabName as varchar(100)
Declare @colName as varchar(100)
Declare @tabid as int
Declare cursorTables Cursor
for
select t.object_id , t.name , c.name from sys.tables t inner join sys.columns c on t.object_id = c.object_id
open cursorTables
Fetch Next from cursorTables into
@tabid,@tabName,@colName
while @@Fetch_Status = 0
Begin
declare @query as nVarchar(1000)
set @query = 'Insert into #Temp SELECT ''' + @tabName + ''' , '''+ @colName +''', ' + @colName + ', COUNT([' + @colName +']) AS Expr1 FROM [' + @tabName+ '] group by [' + @colName + ']'
print @query
exec sp_executesql @query
Fetch Next from cursorTables into
@tabid,@tabName,@colName
End
Close cursorTables
Deallocate cursorTables
select * from #temp
drop table #temp
在PK值上產生一些不太有用的結果,我懷疑它不適用於大於varchar(1000)的列但是對我的dbs的fe有效
這個版本是一個很好的片段:
DECLARE @sql NVARCHAR(MAX) = N'';
SELECT @sql += 'SELECT ''' + t.name + ''', ''' + c.name + ''', ' + c.name + ', COUNT(' + c.name + ') AS C FROM ' + QUOTENAME(s.name) + '.' + QUOTENAME(t.name) + ' GROUP BY ' + c.name + ';' + CHAR(13)
FROM sys.tables AS t
INNER join sys.columns c on t.object_id = c.object_id
INNER JOIN sys.schemas AS s ON t.[schema_id] = s.[schema_id]
WHERE s.name LIKE 'stage' AND t.name LIKE 'table' AND c.name LIKE '%whatever%';
--PRINT @sql;
EXEC sp_executesql @sql
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.