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[英]How to convert std::string with hex values into std::vector<unsigned char>
[英]How to split a hex string into std::vector?
給定一個十六進制的std::string
例如"09e1c5f70a65ac519458e7e53f36"
,我如何將其拆分為兩位數的塊並將其存儲到std::vector<uint8_t>
?
我以塊大小的步長循環遍歷字符串,但是我不知道如何將十六進制塊轉換為數字。 到目前為止,這就是我所擁有的。
vector<byte> vectorify(string input, int chunk = 2)
{
vector<uint8_t> result;
for(size_t i = 0; i < input.length(); i += chunk)
{
int hex = input.substr(i, chunk);
// ...
}
return result;
}
這是一個班輪:-)
#include <string>
#include <vector>
#include <boost/algorithm/hex.hpp>
int main(int argc, const char * argv[]) {
std::string in("09e1c5f70a65ac519458e7e53f36");
std::vector<uint8_t> out;
boost::algorithm::unhex(in.begin(), in.end(), std::back_inserter(out));
return 0;
}
#include <string>
#include <sstream>
#include <vector>
#include <iomanip>
int main(void)
{
std::string in("09e1c5f70a65ac519458e7e53f36");
size_t len = in.length();
std::vector<uint8_t> out;
for(size_t i = 0; i < len; i += 2) {
std::istringstream strm(in.substr(i, 2));
uint8_t x;
strm >> std::hex >> x;
out.push_back(x);
}
// "out" contains the solution
return 0;
}
兩行就夠了
char str[]="09e1c5f70a65ac519458e7e53f36";
std::vector<uint8_t> fifth (str, str+ sizeof(str) / sizeof(uint8_t) );
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