std ::綁定類中的靜態成員函數

Question

我試圖存儲一個稍后調用的函數，這里是一個片段。

這很好用：

void RandomClass::aFunc( int param1, int param2, double param3, bool isQueued /*= false */ )
{
    /* If some condition happened, store this func for later */
    auto storeFunc = std::bind (&RandomClass::aFunc, this, param1, param2, param3, true);

    CommandList.push( storeFunc );

    /* Do random stuff */
}

但是，如果RandomClass是靜態的，那么我相信我應該這樣做：

void RandomClass::aFunc( int param1, int param2, double param3, bool isQueued /*= false */ )
{
    /* If some condition happened, store this func for later */
    auto storeFunc = std::bind (&RandomClass::aFunc, param1, param2, param3, true);

    CommandList.push( storeFunc );

    /* Do random stuff */
}

但這不起作用，我得到編譯錯誤

錯誤C2668：'std :: tr1 :: bind'：對重載函數的模糊調用

任何幫助贊賞。

Answer 1

指向靜態成員函數的指針類型看起來像是指向非成員函數的指針：

auto storeFunc = std::bind ( (void(*)(WORD, WORD, double, bool))
                              &CSoundRouteHandlerApp::MakeRoute, 
                              sourcePort, destPort, volume, true );

這是一個簡化的例子：

struct Foo
{
  void foo_nonstatic(int, int) {}
  static int foo_static(int, int, int) { return 42;}
};

#include <functional>
int main()
{
  auto f_nonstatic = std::bind((void(Foo::*)(int, int))&Foo::foo_nonstatic, Foo(), 1, 2);
  auto f_static = std::bind((int(*)(int, int, int))&Foo::foo_static, 1, 2, 3);

}