如何比較兩個不同類的對象？

Question

我想制作一個可以輸入一些隨機名稱的程序，然后在接下來的幾行中輸入father > son/daughter 。 然后，程序將從第一個輸入中搜索父親。

例：

米婭安娜
莎恩>安娜

輸出將是：

安娜<莎恩

這是我制作的程序（請注意anak = child; ayah = father; nama = name）：

using namespace std;

class status { 
public:
string ayah, anak1, anak2, anak3;
status (const string& inayah="", const string& inanak1="", const string& inanak2="", const string& inanak3="") : ayah(inayah), anak1(inanak1), anak2(inanak2), anak3(anak3){}
};

class populasi {
string nama1, nama2, nama3, nama4, nama5, nama6;
public:
populasi (const string& innama1="",const string& innama2="",const string& innama3="", const string& innama4="",const string& innama5="",const string& innama6="")
: nama1(innama1), nama2(innama2), nama3(innama3), nama4(innama4), nama5(innama5), nama6(innama6){}



void cek(const status& x)
{
    if( x.anak1() == nama1() ) cout << x.anak1() << " < " << x.ayah() << endl;
    if( x.anak1() == nama2() ) cout << x.anak1() << " < " << x.ayah() << endl;
    if( x.anak1() == nama3() ) cout << x.anak1() << " < " << x.ayah() << endl;
    if( x.anak1() == nama4() ) cout << x.anak1() << " < " << x.ayah() << endl;
    if( x.anak1() == nama5() ) cout << x.anak1() << " < " << x.ayah() << endl;
    if( x.anak1() == nama6() ) cout << x.anak1() << " < " << x.ayah() << endl;

    if( x.anak2 == nama1() ) cout << x.anak2() << " < " << x.ayah() << endl;
    if( x.anak2 == nama2() ) cout << x.anak2() << " < " << x.ayah() << endl;
    if( x.anak2 == nama3() ) cout << x.anak2() << " < " << x.ayah() << endl;
    if( x.anak2 == nama4() ) cout << x.anak2() << " < " << x.ayah() << endl;
    if( x.anak2 == nama5() ) cout << x.anak2() << " < " << x.ayah() << endl;
    if( x.anak2 == nama6() ) cout << x.anak2() << " < " << x.ayah() << endl;

    if( x.anak3 == nama1() ) cout << x.anak3() << " < " << x.ayah() << endl;
    if( x.anak3 == nama2() ) cout << x.anak3() << " < " << x.ayah() << endl;
    if( x.anak3 == nama3() ) cout << x.anak3() << " < " << x.ayah() << endl;
    if( x.anak3 == nama4() ) cout << x.anak3() << " < " << x.ayah() << endl;
    if( x.anak3 == nama5() ) cout << x.anak3() << " < " << x.ayah() << endl;
    if( x.anak3 == nama6() ) cout << x.anak3() << " < " << x.ayah() << endl;
    };  
};

 int main()
 {  
string nama1, nama2, nama3, nama4, nama5, nama6;
fscanf ( stdin, " %s %s %s %s %s %s", &nama1, &nama2, &nama3, &nama4, &nama5, &nama6); 
populasi a (nama1, nama2, nama3, nama4, nama5, nama6);

string ayah, anak1, anak2, anak3;
fscanf ( stdin, " %s > %s %s %s", &ayah, &anak1, &anak2, &anak3); 
status b ( ayah, anak1, anak2, anak3);

fscanf ( stdin, " %s > %s %s %s", &ayah, &anak1, &anak2, &anak3); 
status c ( ayah, anak1, anak2, anak3);

fscanf ( stdin, " %s > %s %s %s", &ayah, &anak1, &anak2, &anak3); 
status d ( ayah, anak1, anak2, anak3);

fscanf ( stdin, " %s > %s %s %s", &ayah, &anak1, &anak2, &anak3); 
status e ( ayah, anak1, anak2, anak3);

fscanf ( stdin, " %s > %s %s %s", &ayah, &anak1, &anak2, &anak3); 
status f ( ayah, anak1, anak2, anak3);

fscanf ( stdin, " %s > %s %s %s", &ayah, &anak1, &anak2, &anak3); 
status g ( ayah, anak1, anak2, anak3);

a.cek(b);
a.cek(c);
a.cek(d);
a.cek(e);
a.cek(f);
a.cek(g);
return 0;
 }

Answer 1

不幸的是，您確實是以非常“ C”的樣式進行此操作的，並且錯過了C ++標准庫用於解析輸入，存儲文本和關聯容器的功能（該功能可以讓您存儲與“鍵”關聯的值，然后找到它們）稍后通過指定相同的“鍵”）。

由於每個人只有一種與他們相關聯的數據-他們的名字-在此程序中不需要用戶定義的類或從中受益。 std::string類可以輕松存儲其名稱。 您的類存儲了多個名稱，但是C ++標准庫容器可以更好地做到這一點。

#include <sstream>
#include <iostream>
#include <map>

int main()
{
     std::string first_line;
     if (!getline(std::cin, line))
     {
          std::cerr << "failed to read a line of names\n";
          return 1;
     }

     // read and remember father/child relationships...
     typedef std::map<std::string, std::string> Map;
     Map child_to_father;
     std::string father, child;
     char c = '>';
     while (iss >> father >> c && c == '>' && iss >> child)
         child_to_father[child] = father;
     if (!is.eof() || is.bad() || c != '>')
     {
         std::cerr << "error reading 'father > child' line\n";
         return 1;
     }

     // now report the matches for names on the first line...
     std::istringstream iss(first_line);
     while (iss >> child)
     {
          Map::const_iterator i = child_to_father.find(name);
          if (i != child_to_father.end())
               std::cout << child << " < " << father << '\n';
     }
}