如何將2個表中的信息放入一個sql查詢中？

Question

我有這2個表，我需要從中獲得船和圖像信息才能在同一sql / loop中顯示。

這可能嗎？ 有內部聯接嗎？

$info1 = mysql_query(" SELECT image1 as image, boat1 as boat FROM all_images ");
$info2 = mysql_query(" SELECT image2 as image, boat2 as boat FROM all_boats_images ");

while($b = mysql_fetch_array($????????)){
 echo $b['boat'].$b['boat'];
} 

Answer 1

只需在表名之前附加數據庫名

即，如果數據庫名稱是db1，表名稱是tb1，則

          SELECT * FROM db1.tb1;

Answer 2

希望這可以幫助：

 $query = mysql_query("SELECT all_images.image1, all_boats_images.image2 AS image FROM all_images, all_boat_images");

 while($b = mysql_fetch_array($query))
    {
      echo $b['boat'];
    }

要縮小結果范圍，請嘗試將$ query更改為：

$query = mysql_query("SELECT all_images.image1, all_boats_images.image2 AS image FROM all_images, all_boat_images WHERE all_images.id = all_boats_images.id AND all_images.id = whatever_id_you_are_searching_for");

Answer 3

我認為您想使用工會，因為您評論說這些表不相關

SELECT image1 as image, boat1 as boat FROM all_images
union all
SELECT image2 as image, boat2 as boat FROM all_boats_images