[英]Retrieving data from a database with ajax
當數據庫已經循環時,為什么不能從數據庫中獲取所有數據? 我只從數據庫中獲取最后一行數據。
HTML:
<div id="registerlist">
</div>
<script>
$.getJSON("http://url/getapplicantdetails.php?callback=?",{},function(data)
{
var rlist = (data.fullname);
var fullndear = document.getElementById('registerlist');
fullndear.innerHTML = rlist;
});
</script>
PHP:
<?php
header('Access-Control-Allow-Origin: *');
header("Content-Type: application/json");
include_once ("dbcon.php");
$sql = "SELECT * FROM tblregistered";
$select = mysql_query($sql);
while($row = mysql_fetch_array($select))
{
echo $_GET['callback']." (".json_encode(array("fullname"=>$row['fullname'],"email"=>$row['email'],"username"=>$row['username'],)).");";
}
?>
任何人都可以告訴我我想念的是什么或出了什么問題。 提前致謝。
您正在瀏覽器中顯示數據,這是錯誤的顯示json多維數組的更多記錄,並在循環中對其進行處理。
<?php
header('Access-Control-Allow-Origin: *');
header("Content-Type: application/json");
include_once ("dbcon.php");
//local array
$data = array();
$sql = "SELECT * FROM tblregistered";
$select = mysql_query($sql);
while($row = mysql_fetch_array($select))
{
//fill the local array
$data[] = array("fullname"=>$row['fullname'],"email"=>$row['email'],"username"=>$row['username']);
}
//display the output
echo json_encode($data);
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