[英]Yii Active Record - WHERE on relations-table
我的mysql數據庫中有以下表格:
category (id,name, url)
recipe_categories (category_id, recipe_id)
recipes (id, name, description)
我要實現的SQL語句如下所示:
SELECT * FROM recipes r
INNER JOIN recipe_categories cr ON cr.recipe_id = r.id
INNER JOIN category c ON c.id = cr.category_id
WHERE c.url = "google.de"
兩種模式:
<?php
class RecipeCategoryModel extends CActiveRecord
{
public static function model($className=__CLASS__)
{
return parent::model($className);
}
public function tableName()
{
return 'recipe_categories';
}
public function relations()
{
return array(
'recipes' => array(self::MANY_MANY , 'RecipeModel', 'recipe_has_categories(recipe_category_id,recipe_id)'),
);
}
public function getActive() {
return RecipeCategoryModel::model()->with(array(
'recipes'=>array(
'joinType'=>'INNER JOIN',
),
))->findAll();
}
}
?>
<?php
class RecipeModel extends CActiveRecord
{
public static function model($className=__CLASS__)
{
return parent::model($className);
}
public function tableName()
{
return 'recipes';
}
public function relations()
{
return array(
'categories' => array(self::MANY_MANY , 'RecipeCategoryModel', 'recipe_has_categories(recipe_id,recipe_category_id)'),
);
}
public function getMainImage() {
}
}
?>
問題出在哪里。 如何通過ActiveRecord(with(),CDbCriteria,...)實現這一目標?
在考慮答案時,我不得不稍微清理一下數據庫表和模型名稱,因為所提供的代碼在測試時會導致一些錯誤。 但是我已經能夠生成所需的SQL語句-但是請記住,在使用Yii的ActiveRecord時,它使用了自己的語法和表別名。
我得到的結果是:
SELECT `t`.`id` AS `t0_c0`, `t`.`name` AS `t0_c1`, `t`.`description` AS `t0_c2`, `categories`.`id` AS `t1_c0`, `categories`.`name` AS `t1_c1`, `categories`.`url` AS `t1_c2`
FROM `recipe` `t`
INNER JOIN `recipe2category` `categories_categories` ON (`t`.`id`=`categories_categories`.`recipe_id`)
INNER JOIN `category` `categories` ON (`categories`.`id`=`categories_categories`.`category_id`)
WHERE (categories.url = 'google.de')
要在Yii CActiveRecord調用中獲取WHERE語句,您需要在CDbCriteria或FindAll()參數中添加“條件”或“比較”。 參見http://www.yiiframework.com/doc/api/1.1/CDbCriteria#condition-detail和http://www.yiiframework.com/doc/api/1.1/CDbCriteria#addCondition-detail
例如:
$Criteria = new CDbCriteria;
$Criteria->with = array(
'categories' => array(
'joinType' => 'INNER JOIN'
),
);
$Criteria->condition = 'categories.url = :url';
$Criteria->params = array(
':url' => 'google.de',
);
$Recipes = Recipe::model()->findAll($Criteria);
但是,要使該代碼起作用,您將需要我清理過的數據庫表和模型:
TABLE recipe - id, name, description
TABLE recipe2category - category_id, recipe_id
TABLE category - id, name, url
模型Recipe.php:
<?php
class Recipe extends CActiveRecord
{
public static function model($className=__CLASS__)
{
return parent::model($className);
}
public function tableName()
{
return 'recipe';
}
public function relations()
{
return array(
'categories' => array(self::MANY_MANY , 'RecipeCategory', 'recipe2category(recipe_id,category_id)'),
);
}
}
?>
模型RecipeCategory.php:
<?php
class RecipeCategory extends CActiveRecord
{
public static function model($className=__CLASS__)
{
return parent::model($className);
}
public function tableName()
{
return 'category';
}
public function relations()
{
return array(
'recipes' => array(self::MANY_MANY , 'Recipe', 'recipe2categoy(category_id,recipe_id)'),
);
}
}
?>
希望這是有用的。
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