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[英]Not working, string in android when making Post request with Json Object
[英]Making a POST request in Android
我正在嘗試向我的Android
應用程序中的服務器發出POST
請求,但沒有發生。 下面是代碼-
try{
View p = (View) v.getRootView();
EditText usernamefield = (EditText)p.findViewById(R.id.username);
String username = usernamefield.getText().toString();
EditText passwordfield = (EditText)p.findViewById(R.id.pass);
String password = passwordfield.getText().toString();
String apiKey = "ac96d760cb3c33a1ee988750b0b2fd12";
String secret = "cd9118e8d1d32d003e0ed54a202c2bf8";
Log.i(TAG,password);
String authToken = computeMD5hash(username.toLowerCase()).toString()+computeMD5hash(password).toString();
String authSig = computeMD5hash("api_key"+apiKey+"authToken"+authToken+"method"+"auth.getMobileSession"+"username"+username+secret).toString();
Log.i(TAG,authToken);
HttpClient client = new DefaultHttpClient();
Log.i(TAG,"after client1");
HttpPost post = new HttpPost("http://ws.audioscrobbler.com/2.0/");
Log.i(TAG,"after client2");
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("method", "auth.getMobileSession"));
nameValuePairs.add(new BasicNameValuePair("api_key", apiKey));
nameValuePairs.add(new BasicNameValuePair("api_sig", authSig));
nameValuePairs.add(new BasicNameValuePair("format", "json"));
nameValuePairs.add(new BasicNameValuePair("authToken", authToken));
nameValuePairs.add(new BasicNameValuePair("username", username));
post.setEntity(new UrlEncodedFormEntity(nameValuePairs));
Log.i(TAG,post.getURI().toString()); //logs the URL
HttpResponse response = client.execute(post);
int status = response.getStatusLine().getStatusCode();
Log.i(TAG,"Status code is"+status);
Log.i(TAG,"after post");
InputStream ips = response.getEntity().getContent();
BufferedReader buf = new BufferedReader(new InputStreamReader(ips,"UTF-8"));
if(response.getStatusLine().getStatusCode()!= org.apache.commons.httpclient.HttpStatus.SC_OK)
{
Log.i(TAG,"bad http response");
Toast.makeText(getApplicationContext(),"bad httpcode",Toast.LENGTH_LONG).show();
throw new Exception(response.getStatusLine().getReasonPhrase());
}
StringBuilder sb = new StringBuilder();
String s;
while(true)
{
s = buf.readLine();
if(s==null || s.length()==0)
break;
sb.append(s);
}
buf.close();
ips.close();
System.out.print(sb.toString());
}
catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
catch(NoSuchAlgorithmException e)
{
}
catch(Exception e){
}
該代碼將一直執行到Log.i(TAG,post.getURI().toString())
日志語句。 它將打印出所創建的URL- http://ws.audioscrobbler.com/2.0/ 。 沒有附加參數(很奇怪)。
我不知道使用NameValuePairs向URL添加參數的實現有什么問題。
我確實有一種簡單的方法將數據發布到服務器。 請使用它,讓我知道這是否對您有用:
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("method", "auth.getMobileSession"));
nameValuePairs.add(new BasicNameValuePair("api_key", apiKey));
nameValuePairs.add(new BasicNameValuePair("api_sig", authSig));
nameValuePairs.add(new BasicNameValuePair("format", "json"));
nameValuePairs.add(new BasicNameValuePair("authToken", authToken));
nameValuePairs.add(new BasicNameValuePair("username", username));
//call to method
JSONObject obj = makeHttpRequest(nameValuePairs, "http://ws.audioscrobbler.com/2.0/", "POST");
public static JSONObject makeHttpRequest(List<NameValuePair> params, String url, String method) {
InputStream is = null;
JSONObject jObj = null;
String json = "";
// Making HTTP request
try {
// check for request method
if(method == "POST"){
// request method is POST
// defaultHttpClient
url = url.trim();
Log.e("FETCHING_DATA_FROM",""+url.toString());
HttpPost httpPost = new HttpPost(url);
HttpParams httpParameters = new BasicHttpParams();
// Set the timeout in milliseconds until a connection is established.
int timeoutConnection = 600000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT)
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 600000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
httpPost.setEntity(new UrlEncodedFormEntity(params,"utf-8"));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}else if(method == "GET"){
// request method is GET
if(params!=null){
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
}
HttpGet httpGet = new HttpGet(url);
Log.e("FETCHING_DATA_FROM",""+url.toString());
HttpParams httpParameters = new BasicHttpParams();
// Set the timeout in milliseconds until a connection is established.
int timeoutConnection = 600000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT)
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 600000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
return jObj;
}
您必須將這段代碼包裝在try catch塊中,因為這里可能引發一些異常。 關於哪個是我不確定的問題,但是這是一些可能導致問題的常見問題,您需要提供更多信息,然后才能看到它是哪個:1)在較新版本的Android上,如果您進行thisw調用在主UI線程中,它將引發NetworkOnMainThread異常。 您必須在后台線程上執行聯網代碼。 2)您未在清單中聲明Internet許可,因此它將引發安全異常。
您需要查看logcat中的異常或在try / catch的catch部分中中斷。 如果您的漁獲看起來像這樣:
catch(Exception e)
{
}
然后它將默默地吃掉異常,並且不會給您任何問題的跡象。
只需嘗試使用JsonStringer.Like:
HttpPost request = new HttpPost("http://ws.audioscrobbler.com/2.0/something_here");
request.setHeader("Accept", "application/json");
request.setHeader("Content-type", "application/json");
JSONStringer vm;
try {
vm = new JSONStringer().object().key("method")
.value("auth.getMobileSession").key("api_key").value(apikey)
.key("api_sig") .value(authSig).key("format").value("json").key(authToken).value(authToken).key("username").value(username)
.endObject();
StringEntity entity = new StringEntity(vm.toString());
request.setEntity(entity);
HttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(request);
就像Kaediil所說的那樣,在響應代碼中加入try and catch子句。
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