[英]PHP If statements not showing correct results
我有這些PHP if語句,當我回顯$percentage
它顯示100但它的回聲
echo 'Over Allowance';
echo '<br>INSERT into customer_billing';
並不是
echo 'Reached Allowance';
if($percentage >= '80' and $percentage <= '100') {
echo '<strong>'.$customer["company"].'</strong><br>';
echo 'Approaching Allowance';
echo 'check customer_billing and remove';
}
//if its 100%
elseif($percentage == '100') {
echo '<strong>'.$customer["company"].'</strong><br>';
echo 'Reached Allowance';
echo 'check customer_billing and remove';
}
//if its more than 100%
elseif($percentage > '100') {
echo '<strong>'.$customer["company"].'</strong><br>';
echo 'Over Allowance';
echo '<br>INSERT into customer_billing';
}
//or if the limit is less than the percentage
//this does nothing at all
elseif($percentage < $result["soundfiles_max"]) {
//do nothing
echo 'check customer_billing and remove';
}
我究竟做錯了什么?
你可以刪除第一個相同的法則,
if($percentage >= '80' && $percentage < '100') {
因為你使用的是> =運算符,你應該使用整數而不是文本,並刪除那些數字上的'',所以從'80'到80只
if($percentage >= 80 && $percentage <= 100) {
echo '<strong>'.$customer["company"].'</strong><br>';
echo 'Approaching Allowance';
echo 'check customer_billing and remove';
}
//if its 100%
elseif($percentage == 100) {
echo '<strong>'.$customer["company"].'</strong><br>';
echo 'Reached Allowance';
echo 'check customer_billing and remove';
}
//if its more than 100%
elseif($percentage > 100) {
echo '<strong>'.$customer["company"].'</strong><br>';
echo 'Over Allowance';
echo '<br>INSERT into customer_billing';
}
//or if the limit is less than the percentage
//this does nothing at all
elseif($percentage < $result["soundfiles_max"]) {
//do nothing
echo 'check customer_billing and remove';
}
嘗試刪除數字值周圍的引號,例如:
if($percentage >= '80' and $percentage <= '100') {
變為:
if($percentage >= 80 and $percentage <= 100) {
省略百分比值的引號,因為它們是整數。 喜歡
if($percentage >= 80 and $percentage <= 100)
如果$ percentage值為100,則不會轉到elseif語句,因為您在1st語句中檢查的值大於等於100。
參考浮點數 ,
永遠不要將浮點數結果信任到最后一位,並且不要直接比較浮點數是否相等。 如果需要更高的精度,可以使用任意精度數學函數和gmp函數。
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