簡單的隨機數游戲程序

Question

這是我的代碼，這是一個簡單的數字游戲，用戶嘗試猜測隨機數，但是我無法弄清楚為什么您永遠不會贏。.我有兩件事無法解決1）用戶從未猜過正確的數字2）我想嘗試3次嘗試的上限，盡管我似乎無法掌握我所忽略的內容

// C_program_random_number_game

#include<stdio.h>
#include<time.h>
#include <stdlib.h>




int main(){

srand(time(NULL));
int num1,x;
char game, cont, replay;
printf("Would you like to play a game? : ");
scanf("%c",&game);
if (game == 'y' || game == 'Y'){

    printf("\nThe rules are simple. You have have 5 tries to guess the computers number. \n \n If you succeed you win the game, if you dont you lose the game. Good luck!");
    do{
    int r = rand()%25 +1;
    printf("\n\nEnter a number between 1 and 5 : ");
    scanf("%d",&num1);
    do{
    for(x=1; x<=3; x++){

    if(num1 < r){
        printf("\nClose! try a little higher... : ");
    }
    else if (num1 > r){
        printf("\nClose! try a little lower...: ");
    }
    scanf("%d",&num1);
    }
    }while(num1!=r || x <= 3);
    printf("\nWinner! >> you entered %d and the computer generated %d! \n",num1, r);
    printf("\nWould you like to play again? (y or n) : ");
    scanf("\n%c",&replay);
    }while(replay == 'y'|| replay == 'Y');
}
    printf("Thanks for playing! ");

    if (game == 'n' || game == 'N'){
    printf("Okay, maybe next time! ");
    }
    return 0;
}

Answer 1

一個明確的問題是格式說明符不正確：

scanf("&d",&num1);

應該：

scanf("%d",&num1);

此外， while循環中的最后2個條件將永遠不會被評估，因為如果猜測等於隨機數，則它不會進入循環。 可以使用do-while循環來無限循環，並根據用戶輸入break它。 記住要在循環中接受用戶輸入以進行猜測。

Answer 2

有很多缺陷，這是您要查找的代碼：

while(num1 != r){
    if(num1 < r){
        printf("higher... : ");
    }
    else{
        printf("lower...: ");
    }
    scanf("%d",&num1);
}
printf("Winner! >> you entered %d and the computer generated %d! \n",num1, r);
printf("Would you like to play again? (y or n) : ");
scanf("%c",&replay);

正如我在上面的注釋中所指出的那樣，以前，在while循環內，永遠不會有num1 == r的時間，因此里面的if語句永遠不會為真。 現在，循環jsut到達數字后就停止了。