VBA在兩列中刪除重復項

Question

我想使用VBA在B1 = B2 AND C1 = C2時刪除B和CEg兩列中的重復項，然后應刪除B2 AND C2數據。 但是，當B1！= B2 AND C1 = C2時，不應刪除B2 AND C2，因為B2的值與B1不同。 現在我正在使用下面的代碼，但是它並沒有做我想要的正確的事情。它僅刪除C列中的重復數據。

Sub ()

Dim rCell As Range

With Worksheets("Sheet1")
  For Each rCell In Range("B1:C20") 
  rCell.EntireColumn.RemoveDuplicates 1
  Next rCell
End With

End Sub

有誰知道如何更改代碼以使其正常工作？

提前致謝！

Answer 1

我讓你親密的...

Sub RemoveDups_Copy(sSheet As String)
Dim vArray As Variant
Dim x As Long, y As Integer
Dim sTest As String

Worksheets(sSheet).Select
x = 1
Do While Cells(x + 1, 1) <> ""
x = x + 1
Loop

lastRow = x
If lastRow = 1 Then lastRow = 2
lastColumn = Cells(1, Columns.Count).End(xlToLeft).Column

ReDim vArray(1 To lastRow, 1 To lastColumn)
Set dRemove = CreateObject("Scripting.Dictionary")
Set dRemoveIndex = CreateObject("Scripting.Dictionary")


For x = 2 To lastRow
    sTest = ""
    For y = 1 To lastColumn
        sTest = sTest & "|" & Cells(x, y).Text
    Next y
    If dRemove(sTest) = "Remove" Then dRemoveIndex(x) = "Remove"
    dRemove(sTest) = "Remove"
Next x

i = 0
For x = 1 To lastRow
    If dRemoveIndex(x) <> "Remove" Then
        i = i + 1
        For y = 1 To lastColumn
            vArray(i, y) = Cells(x, y).Text
        Next y
    End If
Next x

Range(Cells(2, 1), Cells(lastRow, lastColumn)).ClearContents
Call RemoveDups_Paste(1, 1, vArray)

End Sub

Sub RemoveDups_Paste(x As Integer, y As Integer, Arr As Variant)
    Set Rng = Range(Cells(x, y), Cells(UBound(Arr, 1) - LBound(Arr, 1) + x, UBound(Arr, 2) - LBound(Arr, 2) + y))
    Rng.Resize(UBound(Arr, 1) - LBound(Arr, 1) + 1, UBound(Arr, 2) - LBound(Arr, 2) + 1) = Arr
End Sub

這會將所有原始（或非重復）數據記錄到一個數組中，清除數據，然后將其粘貼為一個范圍，而不是單獨粘貼。 應該跑得快。