PHP拆分字符串

Question

所以我有以下字符串：

{family:Open Sans,name:Open Sans,import_family:Open+Sans:300,300italic,regular,italic,600,600italic,700,700italic,800,800italic,classname:opensans}

我想對其進行“向量化”，所以也許看起來像這樣：

XX['family'] = "Open Sans',
XX['name'] = 'Open Sans',
XX['import_family'] = 'Open+Sans:300,300italic,regular,italic,600,600italic,700,700italic,800,800italic',
XX['classname'] = 'opensans';

關於如何在PHP中實現此目標的任何想法？ 這讓我感到不安，在過去的兩個小時里一直試圖用正則表達式解決這個問題，但到目前為止沒有任何結果。

提前致謝！

Answer 1

這是您可以使用的這種格式的簡單解析器。 它將處理所有字段和值，並將它們作為鍵/值數組返回。 假定字符串以大括號開頭和結尾，並使用field:optional:optional,a,b,c格式。

<?php
    header('Content-Type: text/plain');

    function parse($str) {
        $obj = [];

        $str = substr($str, 1, -1);
        $candidates = explode(',', $str);

        $lastKey = null;

        foreach ($candidates as $candidate) {
            if (strpos($candidate, ':')) {
                $parts = explode(':', $candidate);
                $key = $parts[0];
                $value = substr($candidate, strlen($key) + 1);

                $obj[$key] = $value;
                $lastKey = $key;
            } else {
                $obj[$lastKey] .= ',' . $candidate;
            }
        }

        return $obj;
    }

    $example = '{family:Open Sans,name:Open Sans,import_family:Open+Sans:300,300italic,regular,italic,600,600italic,700,700italic,800,800italic,classname:opensans}';
    print_r(parse($example));
?>

您指定的示例字符串的輸出：

Array
(
    [family] => Open Sans
    [name] => Open Sans
    [import_family] => Open+Sans:300,300italic,regular,italic,600,600italic,700,700italic,800,800italic
    [classname] => opensans
)

Answer 2

嘗試這個：

$s = "{family:Open Sans,name:Open Sans,import_family:Open+Sans:300,300italic,regular,italic,600,600italic,700,700italic,800,800italic,classname:opensans}";
$s = rtrim(ltrim($s, '{'), '}');

preg_match_all('#([^:,]+):((?:(?!(,[^:,]+:)).)*)#', $s, $matches);
$vector = array_combine($matches[1], $matches[2]);

編輯

正如HamZa 在這里說明的，一個較短的正則表達式是：

([^:,]+):(.+?)(?=,[^,]+:|$)