Python代碼無法正常工作

Question

由於某種原因，此代碼將無法正常工作？ 我試圖返回1並中斷，但是由於某種原因它給了我一個錯誤，如果數字太長但我不希望這樣做，我希望代碼返回到開頭。

# Find the cube root of a perfect cube

x = int(input('Enter an integer: '))
if x > 5000:
     break:
     print('too long')
 ### this code is broken ^^^^^



ans = 0
while ans**3 < x:
    ans = ans + 1
if ans**3 != x:
    print(str(x) + ' is not a perfect cube')
else:
    print('Cube root of ' + str(x) + ' is ' + str(ans))


IndentationError: unexpected indent
>>> runfile('/home/dux/pyyyyy.py', wdir=r'/home/dux')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 540, in runfile
    execfile(filename, namespace)
  File "/home/dux/pyyyyy.py", line 7
    print('wrong'):
                  ^
SyntaxError: invalid syntax
>>> runfile('/home/dux/pyyyyy.py', wdir=r'/home/dux')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 540, in runfile
    execfile(filename, namespace)
  File "/home/dux/pyyyyy.py", line 7
    break:
         ^
SyntaxError: invalid syntax
>>> runfile('/home/dux/pyyyyy.py', wdir=r'/home/dux')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 540, in runfile
    execfile(filename, namespace)
  File "/home/dux/pyyyyy.py", line 8
    print('wrong')
    ^
IndentationError: unexpected indent
>>> runfile('/home/dux/pyyyyy.py', wdir=r'/home/dux')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 540, in runfile
    execfile(filename, namespace)
  File "/home/dux/pyyyyy.py", line 7
    break:
         ^
SyntaxError: invalid syntax
>>> 

Answer 1

我認為您要在此處檢查用戶是否輸入了有效數字。 嘗試：

while True:
    x = int(input('Enter an integer: '))
    if x > 5000:
       print('too long')
    else:
       break

Answer 2

中斷將停止循環。 由於您的代碼不在循環中，因此我看不到您為什么要使用它。 另外，休息后不需要冒號。 以便您知道我將舉一個例子。

count = 0
while True:
    print('Hello') #Prints Hello
    if count == 20:  #Checks if count is equal to 20
        break #If it is: break the loop
    count += 1 #Add 1 to count

當然，僅需進行while count < 20:就可以更輕松地完成此操作while count < 20:但是我在說明一個要點。

編輯：另外，查看收到的其他一些錯誤， print后也不需要冒號。