[英]MYSQL: Query two tables and join results from second table to an array
[英]Is there a way to query a MySQL DB twice and add the results from the second query to the same array as the results from the first query?
我在這里按名稱搜索數據庫中的用戶。 我有preg_split()尋找名字和姓氏之間的空間以將它們分開並分別搜索名稱,但是我想對其進行設置,以便如果用戶只輸入名字或姓氏,它將搜索輸入的單個名稱的“ first_name”和“ last_name”字段。 “ Shannon Phillips”將在firstname中搜索Shannon,在last_name中搜索Phillips,但是如果我只是放置Phillips,我希望它在first_name和last_name中搜索Phillips。 我假設我只查詢數據庫兩次,然后以某種方式將第二個查詢的結果附加到第一個查詢的末尾。
function nameProcess(){
if($_SESSION['search_engine_option'] == 'name'){
$name = preg_split("/[\s,]+/", $_SESSION['search_engine_input']);
if(empty($name['0'])){
$first = db_query('SELECT * FROM {tls_active_applicants} WHERE `first_name` = `'.$name['1'].'`');
$last = db_query('SELECT * FROM {tls_active_applicants} WHERE `last_name` = `'.$name['1'].'`');
}elseif(empty($name['1'])){
$first = db_query('SELECT * FROM {tls_active_applicants} WHERE `first_name` = `'.$name['0'].'`');
$last = db_query('SELECT * FROM {tls_active_applicants} WHERE `last_name` = `'.$name['0'].'`');
}
}
為什么不使用OR?
if(empty($name['0'])){
$first = db_query('SELECT * FROM {tls_active_applicants} WHERE `first_name` = `'.$name['1'].'` OR `last_name` = `'.$name['1'].'`');
}elseif(empty($name['1'])){
$first = db_query('SELECT * FROM {tls_active_applicants} WHERE `first_name` = `'.$name['0'].'` OR `last_name` = `'.$name['0'].'`');
}
您可以使用union ,但是在這種情況下,您可以使用'OR'將兩個查詢合並為一個:
SELECT * FROM {tls_active_applicants}
WHERE `first_name` = `'.$name['0'].'`
OR `last_name` = `'.$name['0'].'`
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