如何查詢外鍵並獲取相應的行

Question

我的PHP查詢有問題。 我只需要在列表視圖中獲取被點擊患者的處方即可。

這是處方的表格結構。

我需要ID為79的患者才能顯示他所有的相應處方。 請幫我。

這是PHP。

<?php

/*
 * Following code will list all the products
 */

// array for JSON response
$response = array();


// include db connect class
require_once __DIR__ . '/db_connect.php';

// connecting to db
$db = new DB_CONNECT();

if (isset($_GET["uid"])) {
    $uid = $_GET['uid'];

// get all products from products table

$result = mysql_query("select * from prescription") or die(mysql_error());

// check for empty result
if (mysql_num_rows($result) > 0) {
    // looping through all results
    // products node
    $response["prescription"] = array();

    while ($row = mysql_fetch_array($result)) {
        // temp user array
        $prescription = array();
        $prescription["pres_id"] = $row["pres_id"];
        $prescription["pres_name"] = $row["pres_name"];
        //$product["price"] = $row["price"];


        // push single product into final response array
        array_push($response["prescription"], $prescription);
    }
    // success
    $response["success"] = 1;

    // echoing JSON response
    echo json_encode($response);
} else {
    // no products found
    $response["success"] = 0;
    $response["message"] = "No prescriptions found";

    // echo no users JSON
    echo json_encode($response);
    } 
}else {
    $response["success"] = 0;
    $response["message"] = "Required field(s) is missing";

    // echoing JSON response
    echo json_encode($response);
}
    }
?>

Answer 1

要獲得所選患者的所有處方，不是嗎：

mysql_query("select * from prescription where patient_user_fkey = '$patientID'")or die(mysql_error());

代替：

mysql_query("select * from prescription") or die(mysql_error());