如何優化SQL查詢並向現有數組添加更多數組元素？

Question

我有一個名為$insert_users的數組，如下所示：

Array
(
    [0] => 9def02e6337b888d6dbe5617a172c18d
    [1] => a6d22e4cc3f65778a60b359842bcec82
    [2] => e17151c98358b60910d4d9fd6ae73ac4
    [3] => 472d3d7eca74cb3518bcba787aee8540
)

現在我必須從上面的數組中為每個id發出一個SQL查詢。 我為此編寫的代碼如下：

foreach($insert_users as $key => $value ) {


$sql  = " SELECT DISTINCT ud.user_mobile_number, u.user_first_name, u.user_last_name FROM OCN.users_groups_subscribe ugs JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id WHERE ugs.subscribe_user_id ='".$value."'";

            $this->mDb->Query( $sql);
            $students_data = $this->mDb->FetchArray();                          
            }

它返回$insert_users數組中的單個id元素的數組：

Array
(
    [0] => Array
        (
            [user_mobile_number] => 9929933345
            [user_first_name] => Ashish
            [user_last_name] => Patil
        )

)

但我沒有得到所需格式的陣列。 我想要以下格式的數組$students_data以及數組$insert_users所有值：

Array(  
     [0]=>Array
     (
        [user_full_name] => Ashish Patil //This key should be newly generated & should contain values of keys user_first_name & user_last_name concatenated to each other
        [user_mobile_number] => 9929933345
     )
)

此外，任何人都可以告訴我有沒有辦法只觸發一次SQL查詢並獲得所需的數組，其中包含來自數組$insert_users所有ID的詳細信息？

Answer 1

這不會有幫助：

SELECT DISTINCT ud.user_mobile_number,
CONCAT(u.user_first_name,' ',u.user_last_name) AS user_full_name 
FROM OCN.users_groups_subscribe ugs
JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id
JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id
WHERE ugs.subscribe_user_id ='".$value."'";

Answer 2

而不是做

foreach($insert_users as $key => $value ) {


    $sql  = " SELECT DISTINCT ud.user_mobile_number, u.user_first_name, u.user_last_name FROM OCN.users_groups_subscribe ugs JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id WHERE ugs.subscribe_user_id ='".$value."'";

    $this->mDb->Query( $sql);
    $students_data = $this->mDb->FetchArray();                          
}

做

$value = "'" . implode("','", $insert_users) . "'";
$sql  = " SELECT DISTINCT ud.user_mobile_number, CONCAT(u.user_first_name,' ',u.user_last_name) AS user_full_name FROM OCN.users_groups_subscribe ugs JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id WHERE ugs.subscribe_user_id IN(" .$value . ")";

$this->mDb->Query( $sql);
$students_data = $this->mDb->FetchArray();

現在，您應該在一個查詢中獲得所需的所有結果