鍵入錯誤打開python文件進行讀取

Question

我試圖打開一個文本文件以在Python 3中閱讀時遇到問題。代碼如下：

def main():
the_file = input('What is the name of the file?')

open_file = open(the_file,"r","utf8")
open_file.read()

然后我要調用該函數。

我得到的錯誤是：

Traceback (most recent call last):
  File "/Users/Matthew/Desktop/CaesarCipher.py", line 9, in <module>
    main()
  File "/Users/Matthew/Desktop/CaesarCipher.py", line 7, in main
    open_file = open(encrypted_file,"r","utf8")
TypeError: an integer is required

我不清楚我在哪里使用了不正確的類型...我可以了解為什么它不起作用嗎？

先感謝您。

Answer 1

open()的第三個參數是buffering ：

open(file, mode='r', buffering=-1, encoding=None,
     errors=None, newline=None, closefd=True, opener=None) -> file object

而是將字符編碼作為關鍵字參數傳遞：

with open(the_file, encoding="utf-8") as file:
    text = file.read()

Answer 2

這解決了問題：

open_file = open(the_file,"r")

第三個參數是緩沖區參數 ，而不是編碼？

因此，您可以做的是：

open_file = open(the_file,"r", 1, 'utf-8') # 1 == line Buffered reading

也..
您應該這樣做：

with open(the_file, 'rb') as fh:
    data = fh.read().decode('utf-8')

要么

with open(the_file, 'r', -1, 'utf-8') as fh:
    data = fh.read()

更干凈的是，您可以控制解碼，並且不會以打開的文件句柄或錯誤的編碼結尾。