SpriteKit SKAction在調用completitionBlock之前運行多個動作

Question

我可以打電話

- (void)runAction:(SKAction *)action completion:(void (^)(void))block

但是在4個不同的SKNode上執行操作后如何調用一個完成塊？

基本上，我需要在所有4個SKNode上都調用此方法后執行一些操作

- (void)rotateToSquareIndex:(SquareIndex)squareIndex
{
    self.squareIndex = squareIndex;
    int index        = self.index;
    SKAction * action;
    switch (squareIndex)
    {
        case indexTopLeft:
            action = [SKAction moveTo:CGPointMake(16.f, 16.f) duration:.3];
            index -= 1;
            break;
        case indexTopRight:
            action = [SKAction moveTo:CGPointMake(48.f, 16.f) duration:.3];
            index += 10;
            break;
        case indexBottomRight:
            action = [SKAction moveTo:CGPointMake(48.f, 48.f) duration:.3];
            index += 1;
            break;
        case indexBottomLeft:
            action = [SKAction moveTo:CGPointMake(16.f, 48.f) duration:.3];
            index -= 10;
            break;
        default:
            break;
    }
    self.index = index;

    [self runAction:action];
}

Answer 1

好的，我不認為有任何內置的或“性感的”方式來實現您所追求的目標，但是至少我認為這是一種可行的解決方案：

您需要一個可變數組，如果按照我的方式編寫代碼，則需要一個私有屬性， squareIndexesRotated

- (void)rotateToSquareIndex:(SquareIndex)squareIndex
{
    self.squareIndex = squareIndex;
    int index        = self.index;
    NSNumber *indexNumber = [NSNumber numberWithInt:index];
    if (![self.squareIndexesRotated containsObject:indexNumber]){
        [self.squareIndexesRotated addObject:indexNumber];
    }

    // your action + switch stuff

    if ([self.squareIndexesRotated count] == 4){
        // Do whatever you want here...
    }
}

Answer 2

看起來您正在嘗試執行以下操作。

    YourAction = [SKAction moveTo:CGPointMake(100, 280)duration:5.0];

    SKAction *completion = [SKAction runBlock:^{

    }];

    SKAction *sequence = [SKAction sequence:@[ YourActions ,etc... ]];
    [YourNode runAction:sequence];