簡體   English   中英

PDO無法訪問數據庫連接實例

[英]PDO can't access the database connection instance

我有一個數據庫包裝程序,還有一個獲取PDO連接實例的靜態方法。 Howewer,我想進行PDO查詢時無法訪問它。

這是數據庫類的一部分:

class DB {
private static $_instance = null;
private $_pdo,
        $_query,
        $_error = false,
        $_results,
        $_count =0;


private function __construct() {
    try {
        $this->_pdo = new PDO('mysql:host='.Config::get('mysql/host').';dbname='.Config::get('mysql/db'),Config::get('mysql/username'),Config::get('mysql/password'));

    } catch (PDOException $e) {
        die($e->getMessage());

    }
}

public static function getInstance() {
    if(!isset(self::$_instance)) {
        self::$_instance = new DB();

    }
    return self::$_instance;
}

這是我的查詢:

    $pdo = DB::getInstance();

    $statement = $pdo->prepare("select surname from staff_info where fname = :name");
    $statement->execute(array(':name' => Input::get('name')));
    $total = $statement->rowCount();

   while ($row = $statement->fetch(PDO::FETCH_ASSOC)) { 
            echo $row['surname'].'</br>';

    }

但是運行查詢時出現此錯誤:

致命錯誤:調用未定義的方法DB :: prepare()

我做錯了什么? 有什么幫助嗎?

但這在我這樣做時有效

$dsn = 'mysql:host=localhost;dbname=cois';
$user = 'root';
$password = '';
$pdo = new PDO($dsn, $user, $password);


$filmName = "omar";

$statement = $pdo->prepare("select surname from staff_info where fname = :name");
$statement->execute(array(':name' => $filmName));
$total = $statement->rowCount();

while ($row = $statement->fetch(PDO::FETCH_ASSOC)) { 
      echo $row['surname'].'</br>';

 }

這怎么可能?

您在對象DB而不是PDO上調用prepare,我建議將getter添加到類DB中:

public function getPDO(){ 
  return $this->_pdo;
}

並修改准備查詢:

$db = DB::getInstance();
$statement = $db->getPDO()->prepare(...);
private function __construct() {
    try {
         self::$_instance = new PDO('mysql:host='.Config::get('mysql/host').';dbname='.Config::get('mysql/db'),Config::get('mysql/username'),Config::get('mysql/password'));

    } catch (PDOException $e) {
        die($e->getMessage());

    }
}
public static function getInstance() {
    if(!isset(self::$_instance)) {
         new DB();

    }
    return self::$_instance;
}

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM