SMTP密件抄送郵件不起作用

Question

這是發送SMTP郵件以通過用戶身份驗證發送郵件的簡單代碼。 該代碼對於To：可以正常工作，但Bcc：不起作用。 當我們使用普通的php mail（）函數時，我們會將Bcc：包含在標題中。 但是我不確定如何使用密件抄送：這里使用SMTP協議。

$SmtpServer="127.0.0.1";
$SmtpPort="25"; //default
$SmtpUser="username";
$SmtpPass="password";

class SMTPClient
{

function SMTPClient ($SmtpServer, $SmtpPort, $SmtpUser, $SmtpPass, $from, $to, $subject, $body, $bcc)
{

$this->SmtpServer = $SmtpServer;
$this->SmtpUser = base64_encode ($SmtpUser);
$this->SmtpPass = base64_encode ($SmtpPass);
$this->from = $from;
$this->to = $to;
$this->subject = $subject;
$this->body = $body;

if ($SmtpPort == "")
{
$this->PortSMTP = 25;
}
else
{
$this->PortSMTP = $SmtpPort;
}
}

function SendMail ()
{
if ($SMTPIN = fsockopen ($this->SmtpServer, $this->PortSMTP))
{
fputs ($SMTPIN, "EHLO ".$HTTP_HOST."\r\n");
$talk["hello"] = fgets ( $SMTPIN, 1024 );
fputs($SMTPIN, "auth login\r\n");
$talk["res"]=fgets($SMTPIN,1024);
fputs($SMTPIN, $this->SmtpUser."\r\n");
$talk["user"]=fgets($SMTPIN,1024);
fputs($SMTPIN, $this->SmtpPass."\r\n");
$talk["pass"]=fgets($SMTPIN,256);
fputs ($SMTPIN, "MAIL FROM: <".$this->from.">\r\n");
$talk["From"] = fgets ( $SMTPIN, 1024 );
fputs ($SMTPIN, "RCPT TO: <".$this->to.">\r\n");
$talk["To"] = fgets ($SMTPIN, 1024);
fputs($SMTPIN, "DATA\r\n");
$talk["data"]=fgets( $SMTPIN,1024 );
fputs($SMTPIN, "To: <".$this->to.">\r\nBcc: ".$bcc."\r\nFrom: <".$this->from.">\r\nSubject:".$this->subject."\r\n\r\n\r\n".$this->body."\r\n.\r\n");
$talk["send"]=fgets($SMTPIN,256);
//CLOSE CONNECTION AND EXIT ...
fputs ($SMTPIN, "QUIT\r\n");
fclose($SMTPIN);
//
}
return $talk;
}
}

$to = 'abc@abc.com';
$from = 'xyz@xyz.com';
$subject = 'test subject';
$body = 'body';
$bcc = 'aaa@aaa.com, bbb@bbb.com, ccc@.com';
$SMTPMail = new SMTPClient ($SmtpServer, $SmtpPort, $SmtpUser, $SmtpPass, $from, $to, $subject, $body, $bcc);
$SMTPChat = $SMTPMail->SendMail();

上面的代碼

Answer 1

將密件抄送地址放在自己的“ RCPT TO：” SMTP命令中，刪除“密件抄送：”標頭。

無論如何，如果不喜歡SMTP答復代碼，將給火腿（不是垃圾郵件）發件人帶來麻煩。