[英]Not giving desired output in python
該程序應該讀取一個名為year的類別的輸入文件。 因此,如果用戶鍵入198,則輸出應該給出其中包含198的所有年份,例如1981,1982,...等。 但是,產量也增加了199
Sierra Leone WB_LI 0 Africa 1992
Sierra Leone WB_LI 0 Africa 1993
Sierra Leone WB_LI 0 Africa 1994
Sierra Leone WB_LI 0 Africa 1995
Sierra Leone WB_LI 0 Africa 1996
Sierra Leone WB_LI 0 Africa 1997
該文件的每一行包含以下字段,其中字段之間有一個空格:國家(50個字符)收入等級(6個字符)接種百分比(3個字符)區域(25個字符)年份(4個字符)。 所以,我總共有92個字符,我會在88個病房中查看每個字符,並在一年中將它們與字符匹配以找到所需的年份。 我想我的邏輯中可能有一些錯誤,並且還將199視為一個實例。 我不應該使用列表或元組。 只是提交。
以下是我對我的代碼所做的事情:
def main():
#checks if the input file exists or not.
#If the file exists, then the program breaks out of the loop and
#moves on. Otherwise, the program halts with an IOError message.
while True:
try:
input_file=open('measles.txt','r')
break
except IOError:
print("Error opening file:",input_file)
break
f2=input("What is the name of the output file? ")
#checks if the output file exists or not.
#If the file exists, then the program breaks out of the loop and
#moves on. Otherwise, the program halts with an IOError message.
while True:
try:
output_file=open(f2,'w')
break
except IOError:
print("Error opening file:",output_file)
break
#for loop prints all lines of the input file to the output file.
year=str(input('Input year: '))
line=input_file.readline().strip()
while line!="":
for line in input_file:
if year==line[88:92]:
output_file.write(line)
elif year==line[88:91]:
output_file.write(line)
elif year==line[88:90]:
output_file.write(line)
elif year==line[88:89]:
output_file.write(line)
elif year.lower()=="all" or year=="''" or year=='""':
print(line)
line=input_file.readline().strip()
input_file.close()
output_file.close()
main()
有誰可以看看我的代碼,並指出問題? 謝謝這是我正在處理的文件的幾行。
Afghanistan WB_LI 11 Eastern Mediterranean 1980
Afghanistan WB_LI 0 Eastern Mediterranean 1981
Afghanistan WB_LI 8 Eastern Mediterranean 1982
Afghanistan WB_LI 9 Eastern Mediterranean 1983
Afghanistan WB_LI 14 Eastern Mediterranean 1984
Afghanistan WB_LI 14 Eastern Mediterranean 1985
Afghanistan WB_LI 14 Eastern Mediterranean 1986
Afghanistan WB_LI 31 Eastern Mediterranean 1987
Afghanistan WB_LI 34 Eastern Mediterranean 1988
Afghanistan WB_LI 22 Eastern Mediterranean 1989
Afghanistan WB_LI 20 Eastern Mediterranean 1990
Afghanistan WB_LI 19 Eastern Mediterranean 1991
Afghanistan WB_LI 22 Eastern Mediterranean 1992
Afghanistan WB_LI 25 Eastern Mediterranean 1993
Afghanistan WB_LI 40 Eastern Mediterranean 1994
Afghanistan WB_LI 41 Eastern Mediterranean 1995
Afghanistan WB_LI 42 Eastern Mediterranean 1996
Afghanistan WB_LI 38 Eastern Mediterranean 1997
Afghanistan WB_LI 31 Eastern Mediterranean 1998
Afghanistan WB_LI 31 Eastern Mediterranean 1999
Afghanistan WB_LI 27 Eastern Mediterranean 2000
Afghanistan WB_LI 37 Eastern Mediterranean 2001
Afghanistan WB_LI 35 Eastern Mediterranean 2002
Afghanistan WB_LI 39 Eastern Mediterranean 2003
Afghanistan WB_LI 48 Eastern Mediterranean 2004
Afghanistan WB_LI 50 Eastern Mediterranean 2005
Afghanistan WB_LI 53 Eastern Mediterranean 2006
Afghanistan WB_LI 55 Eastern Mediterranean 2007
Afghanistan WB_LI 59 Eastern Mediterranean 2008
Afghanistan WB_LI 60 Eastern Mediterranean 2009
Afghanistan WB_LI 62 Eastern Mediterranean 2010
Afghanistan WB_LI 65 Eastern Mediterranean 2011
Afghanistan WB_LI 68 Eastern Mediterranean 2012
Albania WB_LMI 90 Europe 1980
Albania WB_LMI 90 Europe 1981
Albania WB_LMI 93 Europe 1982
Albania WB_LMI 96 Europe 1983
Albania WB_LMI 96 Europe 1984
Albania WB_LMI 96 Europe 1985
Albania WB_LMI 96 Europe 1986
Albania WB_LMI 96 Europe 1987
Albania WB_LMI 96 Europe 1988
Albania WB_LMI 96 Europe 1989
Albania WB_LMI 88 Europe 1990
Albania WB_LMI 80 Europe 1991
Albania WB_LMI 87 Europe 1992
Albania WB_LMI 76 Europe 1993
Albania WB_LMI 90 Europe 1994
Albania WB_LMI 91 Europe 1995
Albania WB_LMI 92 Europe 1996
Albania WB_LMI 95 Europe 1997
Albania WB_LMI 89 Europe 1998
Albania WB_LMI 85 Europe 1999
Albania WB_LMI 95 Europe 2000
Albania WB_LMI 95 Europe 2001
Albania WB_LMI 96 Europe 2002
Albania WB_LMI 93 Europe 2003
正如我在評論中提到的,您提供的輸入與您的描述不符。 您的代碼顯示從索引88
開始的year
字段,但您提供的輸入只有44個字符長。 我從那里開始。
編輯:這是我如何編寫你的程序,因為你不能使用任何容器。
def filter_results(input_file, output_file, year):
for line in input_file:
if not line: continue # skips if the line is blank
if year == '' or line[88:92].startswith(year) or year.lower() == 'all':
output_file.write(line+"\n")
def main():
year = input("Give me a year: ")
try: infile = open('measles.txt','r')
except IOError: print("Error opening file: measles.txt")
try: outfile = open(input("Name of output file?"),'w')
except IOError: print("Error opening output file")
try: infile,outfile
except NameError: raise IOError("One of the files could not be opened")
filter_results(infile,outfile,year)
outfile.close()
infile.close()
main()
也就是說,我首先閱讀文件並將其寫入dict
。 就像是:
lines = list()
with open('path/to/input_file') as input_file:
for line in input_file:
lines.append(
{"country":line[0:51].strip(),
"income":line[52:58].strip(),
"vaccinated":line[59:62].strip(),
"region":line[63:88].strip(),
"year":line[89:93].strip()}
# I may have screwed up that string splicing -- do one and doublecheck
year = input("Enter a four-digit year (or part thereof): ")
filtered_list = [line for line in lines if line['year'].startswith(year)]
您現有的代碼中也存在一些問題。
while True:
try:
input_file = open("measles.txt")
break # ?
except IOError:
print("Error opening file:",input_file)
break # ?
如果我們在一次迭代后總是打破,為什么我們在這里循環? 放下片刻while True
然后try:except
沒有break
。 如果你需要在異常時暫停程序,那么只需執行except IOError: raise
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