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[英]Android javax.crypto.BadPaddingException: pad block corrupted
[英]javax.crypto.BadPaddingException: pad block corrupted
我正在嘗試加密某些東西,並對其進行解密。 我沒有解密 - 我得到了上面的例外。 我嘗試改變ctLength和ptLength,但無濟於事。 我究竟做錯了什么?
我正在嘗試加密:0 0 0 0 0 0 0 0
private Cipher encrypt(byte[] input)
{
try
{
SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");
// encryption pass
cipher.init(Cipher.ENCRYPT_MODE, key);
byte[] cipherText = new byte[cipher.getOutputSize(input.length)];
int ctLength = cipher.update(input, 0, input.length, cipherText, 0);
ctLength += cipher.doFinal(cipherText, ctLength);
FileOutputStream fs = new FileOutputStream(savedScoresFileName);
fs.write(cipherText);
return cipher;
}
catch (Exception e)
{
Log.e("encrtypt", "Exception", e);
}
return null;
}
private String decrypt()
{
try
{
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");
SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");
byte[] cipherText = new byte[32];
FileInputStream fl = new FileInputStream(savedScoresFileName);
fl.read(cipherText);
cipher.init(Cipher.DECRYPT_MODE, key);
byte[] plainText = new byte[cipher.getOutputSize(32)];
int ptLength = cipher.update(cipherText, 0, 32, plainText, 0);
ptLength += cipher.doFinal(plainText, ptLength);
return new String(plainText).substring(0, ptLength);
}
catch (Exception e)
{
Log.e("decrypt", "Exception", e);
}
return null;
}
這段代碼是從這里復制過來的。
您的代碼存在許多問題,但您的問題是由文件讀取代碼和執行加密和解密的奇怪方法引起的。
不要使用update()
方法,只需使用doFinal()
並更正文件寫入/讀取代碼。 例如,您的解密方法應該類似於:
try {
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");
SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");
// Here you need to accurately and correctly read your file into a byte
// array. Either Google for a decent solution (there are many out there)
// or use an existing implementation, such as Apache Commons commons-io.
// Your existing effort is buggy and doesn't close its resources.
byte[] cipherText = FileUtils.readFileToByteArray(new File(savedScoresFileName));
cipher.init(Cipher.DECRYPT_MODE, key);
// Just one call to doFinal
byte[] plainText = cipher.doFinal(cipherText);
// Note: don't do this. If you create a string from a byte array,
// PLEASE pass a charset otherwise your result is platform dependent.
return new String(plainText);
} catch (Exception e) {
e.printStackTrace();
}
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