如何使用 gitpython 對當前提交與上次提交進行 git diff 比較？

Question

我正在嘗試掌握 gitpython 模塊，

hcommit = repo.head.commit
tdiff = hcommit.diff('HEAD~1')

但是tdiff = hcommit.diff('HEAD^ HEAD')不起作用！！ ('HEAD~ HEAD') .,

我正在嘗試獲取差異輸出！

Answer 1

import git

repo = git.Repo('repo_path')
commits_list = list(repo.iter_commits())

# --- To compare the current HEAD against the bare init commit
a_commit = commits_list[0]
b_commit = commits_list[-1]

a_commit.diff(b_commit)

這將為提交返回一個 diff 對象。 還有其他方法可以實現這一點。 例如（這是從http://gitpython.readthedocs.io/en/stable/tutorial.html#obtaining-diff-information復制/粘貼的）：

``

    hcommit = repo.head.commit
    hcommit.diff()                  # diff tree against index
    hcommit.diff('HEAD~1')          # diff tree against previous tree
    hcommit.diff(None)              # diff tree against working tree

    index = repo.index
    index.diff()                    # diff index against itself yielding empty diff
    index.diff(None)                # diff index against working copy
    index.diff('HEAD')              # diff index against current HEAD tree

``

Answer 2

我想出了如何使用 gitPython 獲取 git diff。

import git
repo = git.Repo("path/of/repo/")

# the below gives us all commits
repo.commits()

# take the first and last commit

a_commit = repo.commits()[0]
b_commit = repo.commits()[1]

# now get the diff
repo.diff(a_commit,b_commit)

瞧！！！

Answer 3

要獲取差異的內容：

import git
repo = git.Repo("path/of/repo/")

# define a new git object of the desired repo
gitt = repo.git
diff_st = gitt.diff("commitID_A", "commitID_B")

Answer 4

對於正確的解決方案（不使用 git 命令回調），您必須使用 create_patch 選項。

將當前索引與之前的提交進行比較：

diff_as_patch = repo.index.diff(repo.commit('HEAD~1'), create_patch=True)
print(diff_as_patch)

Answer 5

很抱歉挖了一個舊線程...如果您需要找出哪些文件發生了更改，您可以使用 diff 對象的.a_path或.b_path屬性，具體取決於您首先提供的是哪個。 在下面的示例中，我將頭部提交用作a因此我查看a .

例如：

# this will compare the most recent commit to the one prior to find out what changed.

from git import repo

repo = git.Repo("path/to/.git directory")
repoDiffs = repo.head.commit.diff('HEAD~1')

for item in repoDiffs:
    print(item.a_path)