從Java Servlet方法doGet返回數據到ajax

Question

我有這樣的功能ajax：

$.ajax({
        url: "associer_type_flux", // It's  my servlet
        dataType : "xml",
        type : "GET",
        data : { },
        success: function(response){
            alert("fine");
        },
        error:  function(data, status, er){
            alert(data+"_"+status+"_"+er);
        }
    });

我的方法doGet在我的servlet中是這樣的：

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    String forward = ""; 
    try {           
        String fluxXML = "";
        ServicesCodeTypeFluxGlobaux servicesCodeTypeFluxGlobaux = new ServicesCodeTypeFluxGlobauxImpl();

            fluxXML = "<lescodetypeflux>";

            fluxXML += "</lescodetypeflux>";
            PrintWriter printWriter  = response.getWriter();
            printWriter.println(fluxXML);

        }
        forward = "/associerCode/accueil_association.jsp";
        getServletContext().getRequestDispatcher(forward).forward(request, response);           
    }
    catch (Exception e) {
        forward = "/erreur.jsp";
        request.setAttribute("msg", e.getMessage());
    }       
}

所以我的問題是，我無法在jsp中獲取數據..但是我不知道如何從doGet方法獲取此數據或返回此數據..現在我有一個警報Error ..

謝謝

Answer 1

一些使其可行的建議-

1. 不要忘記在您的情況下為“ text / xml”或“ application / xml”設置mime類型

2. 您不能同時使用out.println（）和requestdispatcher，因為它將引發異常。 out.println（）將在響應正文中打印該值，但請求分派器會將您重定向到其他頁面，如果使用ajax，您將獲得的是重定向頁面的整個內容。

所以在你的情況下，你應該只使用out.println（）

因此您的最終代碼應如下所示-

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    response.setContentType("application/xml");
    String forward = ""; 
    try {           
        String fluxXML = "";
        ServicesCodeTypeFluxGlobaux servicesCodeTypeFluxGlobaux = new ServicesCodeTypeFluxGlobauxImpl();

            fluxXML = "<lescodetypeflux>";

            fluxXML += "</lescodetypeflux>";
            PrintWriter printWriter  = response.getWriter();
            printWriter.println(fluxXML);
            printWriter.close();
        }        
    }
    catch (Exception e) {
        //print xml with error value
    }       
}