有人可以告訴我我慢跑的百分比查詢有什么問題嗎？

Question

我試圖弄清楚為什么我的總基數和緩慢的查詢（它們內置在主查詢中）給我誇大的結果。 我已經在一個單獨的查詢中運行每個，並且我得到的數字更接近我想要的（但不正確）。 您將需要一些棒球的基礎知識來幫助我！

Select 
      bbat.playerID, 
      bmast.firstname, 
      bmast.lastname, 
      bbat.yearID, 
      bbat.TeamID, 
      bmast.bats, 
      bmast.throws, 
      bfield.POS, 
      bbat.G, 
      bbat.G_batting, 
      bbat.AB, 
      bbat.R, 
      bbat.H, 
      bbat.2B, 
      bbat.3B, 
      bbat.HR, 
      bbat.RBI, 
      bbat.HBP, 
      bbat.SF, 
      (Sum(H)+(Sum(2B)*2)+(Sum(3B)*3)+(Sum(HR)*4)) as 'TB',
      bbat.BB, 
      bbat.SO, 
      (Sum(BB)/Sum(SO)) as 'BB/K', 
      (SUM(H)/Sum(AB)) as 'Avg',
      ((Sum(H)+Sum(BB)+Sum(HBP))/(Sum(AB)+Sum(BB)+Sum(HBP)+Sum(SF))) as 'OBP', 
      (Sum(H)+(Sum(2B)*2)+(Sum(3B)*3)+(Sum(HR)*4))/Sum(AB) as 'Slugging', 
      (((Sum(H)+Sum(BB)+Sum(HBP))/(Sum(AB)+Sum(BB)+Sum(HBP)+Sum(SF)))+((Sum(H)+(Sum(2B)*2)+(Sum(3B)*3)+(Sum(HR)*4))/Sum(AB))) as 'OPS',
      bbat.SB, 
      bbat.CS, 
      (Sum(SB)/(Sum(SB)+Sum(CS))) as 'Stolen Base %', 
      ((Sum(H)+Sum(BB))*(Sum(H)+(Sum(2B)*2)+(Sum(3B)*3)+(Sum(HR)*4)))/(Sum(AB)+Sum(BB)) as 'Runs Created'
   from 
      baseball.batting bbat 
         inner join ( Select PlayerID, 
                             min(nameFirst) as 'firstname', 
                             min(nameLast) as 'lastname', 
                             bats,
                             throws 
                         from 
                            baseball.master
                         group by 
                            playerID, 
                            nameFirst, 
                            nameLast ) bmast
            on bbat.playerID = bmast.PlayerID
         inner join ( Select PlayerID, 
                             POS
                          from baseball.fielding ) bfield
            on bbat.playerID = bfield.playerID
   where 
          yearID = '2013' 
      and AB > 60 
      and POS != 'P'
   Group by 
      bmast.playerID, 
      bmast.firstname, 
      bmast.lastname;

如果您願意，我可以發布我的個人查詢。 請告訴我！

Answer 1

雖然MySQL允許您從GROUP BY排除非聚合字段，但它可能會產生不希望的結果。 起點是將GROUP BY SELECT列表中的所有非聚合字段都包括在內。 您的查詢可能還會有其他問題。

更新：此子查詢是有問題的，您要使用兩個值的MIN() ，但還要對它們進行分組（這會使MIN() ，並且您不按蝙蝠/投擲進行分組。

 Select PlayerID, 
                             min(nameFirst) as 'firstname', 
                             min(nameLast) as 'lastname', 
                             bats,
                             throws 
                         from 
                            baseball.master
                         group by 
                            playerID, 
                            nameFirst, 
                            nameLast ) bmast

Answer 2

我猜你在找這個

 Select 
  bbat.playerID, 
  bmast.firstname, 
  bmast.lastname, 
  bbat.yearID, 
  bbat.TeamID, 
  bmast.bats, 
  bmast.throws, 
  bfield.POS, 
  bbat.G, 
  bbat.G_batting, 
  bbat.AB, 
  bbat.R, 
  bbat.H, 
  bbat.2B, 
  bbat.3B, 
  bbat.HR, 
  bbat.RBI, 
  bbat.HBP, 
  bbat.SF, 
  ((H)+((2B)*2)+((3B)*3)+((HR)*4)) as 'TB',
  bbat.BB, 
  bbat.SO, 
  ((BB)/(SO)) as 'BB/K', 
  ((H)/(AB)) as 'Avg',
  (((H)+(BB)+(HBP))/((AB)+(BB)+(HBP)+(SF))) as 'OBP', 
  ((H)+((2B)*2)+((3B)*3)+((HR)*4))/(AB) as 'Slugging', 
  ((((H)+(BB)+(HBP))/((AB)+(BB)+(HBP)+(SF)))+(((H)+((2B)*2)+((3B)*3)+((HR)*4))/(AB))) as 'OPS',
  bbat.SB, 
  bbat.CS, 
  ((SB)/((SB)+(CS))) as 'Stolen Base %', 
  (((H)+(BB))*((H)+((2B)*2)+((3B)*3)+((HR)*4)))/((AB)+(BB)) as 'Runs Created'
 from 
 ....