搜索聯系人並從android中的電話聯系人獲取聯系人號碼

Question

我正在使用一個應用程序，因此我必須在單擊按鈕時搜索聯系人，然后從電話聯系人中選擇一個聯系人。 最后，我想將其設置為edittext 。我可以從電話聯系人中搜索聯系人，但無法從電話聯系人中獲取聯系人。

活動：

searchBtn.setOnClickListener(new OnClickListener() {

@Override
public void onClick(View v) {
// TODO Auto-generated method stub
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
intent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE);
startActivityForResult(intent,1);

}
});
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
// TODO Auto-generated method stub
super.onActivityResult(requestCode, resultCode, data);

if(requestCode==RESULT_OK){
Uri contactData = data.getData();
Cursor cursor = managedQuery(contactData, null, null, null, null);
cursor.moveToFirst();
String number = cursor.getString(cursor.getColumnIndexOrThrow
(ContactsContract.CommonDataKinds.Phone.NUMBER));

//contactName.setText(name);
ephoneNumber.setText(number);
//contactEmail.setText(email);
}
}

Answer 1

首先為StartActivityForResult設置Intent像這樣

private void pickContact() {
    Intent pickContactIntent = new Intent(Intent.ACTION_PICK, Uri.parse("content://contacts"));
    pickContactIntent.setType(Phone.CONTENT_TYPE); // Show user only contacts w/ phone numbers
    startActivityForResult(pickContactIntent, PICK_CONTACT_REQUEST);
}

然后處理結果來自本地聯系人應用程序的意圖

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    // Check which request it is that we're responding to
    if (requestCode == PICK_CONTACT_REQUEST) {
        // Make sure the request was successful
        if (resultCode == RESULT_OK) {
            // Get the URI that points to the selected contact
            Uri contactUri = data.getData();
            // We only need the NUMBER column, because there will be only one row in the result
            String[] projection = {Phone.NUMBER};

            // Perform the query on the contact to get the NUMBER column
            // We don't need a selection or sort order (there's only one result for the given URI)
            // CAUTION: The query() method should be called from a separate thread to avoid blocking
            // your app's UI thread. (For simplicity of the sample, this code doesn't do that.)
            // Consider using CursorLoader to perform the query.
            Cursor cursor = getContentResolver()
                    .query(contactUri, projection, null, null, null);
            cursor.moveToFirst();

            // Retrieve the phone number from the NUMBER column
            int column = cursor.getColumnIndex(Phone.NUMBER);
            String number = cursor.getString(column);

            // Do something with the phone number...
        }
    }
}

查看其他參考鏈接

鏈接1 鏈接2

Answer 2

巴拉特

您需要獲得以下許可-

android:name="android.permission.READ_CONTACTS"/>

然后，呼叫聯系人選擇器

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);

然后，

@Override
public void onActivityResult(int reqCode, int resultCode, Intent data) {
super.onActivityResult(reqCode, resultCode, data);

switch (reqCode) {
case (PICK_CONTACT) :
   if (resultCode == Activity.RESULT_OK) {
    Uri contactData = data.getData();
    Cursor c =  managedQuery(contactData, null, null, null, null);
     if (c.moveToFirst()) {
      String name = c.getString(c.getColumnIndexOrThrow(People.NAME));
      // TODO Whatever you want to do with the selected contact name.
    }
  }
  break;
  }
 }

或者，您可以通過其他方式使用

Cursor cursor = null;
try {
    cursor = context.getContentResolver().query(Phone.CONTENT_URI, null, null, null, null);
    int contactIdIdx = cursor.getColumnIndex(Phone._ID);
    int nameIdx = cursor.getColumnIndex(Phone.DISPLAY_NAME);
    int phoneNumberIdx = cursor.getColumnIndex(Phone.NUMBER);
    int photoIdIdx = cursor.getColumnIndex(Phone.PHOTO_ID);
    cursor.moveToFirst();
    do {
        String idContact = cursor.getString(contactIdIdx);
        String name = cursor.getString(nameIdx);
        String phoneNumber = cursor.getString(phoneNumberIdx);
        //...
    } while (cursor.moveToNext());  
} catch (Exception e) {
    e.printStackTrace();
} finally {
    if (cursor != null) {
        cursor.close();
    }
}

上面的解決方案很簡單，並且可以用於獲取聯系號碼。

Answer 3

嘗試這個

CursorLoader cursorLoader = new CursorLoader(mActivity,
            CallLog.Calls.CONTENT_URI, null, null, null, null);
managedCursor = cursorLoader.loadInBackground();
int number = managedCursor.getColumnIndex(CallLog.Calls.NUMBER);
int name = managedCursor.getColumnIndex(CallLog.Calls.CACHED_NAME);
String conTactnumber=managedCursor.getString(number);               
String contactname=managedCursor.getString(name);

set permission   
<uses-permission android:name="android.permission.READ_CONTACTS" >
</uses-permission>