在Oracle列CLOB的字段中獲取xmltype

Question

我有一個包含xml格式的列CLOB類型。

我需要用一個簡單的查詢來獲取與此字段不同的所有類型：

防爆。 該字段包含不同的類型：

First record:
<Message type="New Address" xmlns="http://euroconsumers.org/ecommerce/2009/01/scope/messages"><Customer ...

Second record:
<Message type="Added Email" xmlns="http://euroconsumers.org/ecommerce/2009/01/scope/messages"><Customer ...

Third record:
<Message type="New Order" xmlns="http://euroconsumers.org/ecommerce/2009/01/scope/messages"><Customer ...

我想檢索：

New Address
Added Email
New Order

Answer 1

這適用於您的數據：

select xmlquery('/*/@type'
  passing xmltype(<clob column>)
  returning content)
from <your table>;

演示：

create table t42 (clob_col clob);
insert into t42 values ('<Message type="New Address" xmlns="..."><Customer type="x"></Customer></Message>');
insert into t42 values ('<Message type="Added Email" xmlns="..."><Customer></Customer></Message>');
insert into t42 values ('<Message type="New Order" xmlns="..."><Customer></Customer></Message>');

select xmlquery('/*/@type'
  passing xmltype(t42.clob_col)
  returning content)
from t42;

XMLQUERY('/*/@TYPE'PASSINGXMLTYPE(T42.CLOB_COL)RETURNINGCONTENT)
----------------------------------------------------------------
New Address
Added Email
New Order

或這個：

select xmltype(<clob_column>).extract('/*/@type')
from <your table>;

演示：

select xmltype(clob_col).extract('/*/@type')
from t42;

XMLTYPE(CLOB_COL).EXTRACT('/*/@TYPE')
-------------------------------------
New Address
Added Email
New Order

閱讀有關查詢XML的更多信息。