[英]Python check all file with a specific name in a directory
我在目錄( path = 'C://sample'
)中具有三個或更多后綴(“ .txt”,“ .shp”,“ .shx”,“ .dbf”)的文件名( mytest.
)。 我希望列出所有具有相同名稱的文件
我知道使用import glob
可以列出具有特定后綴的所有文件
我的問題是如何在目錄中列出所有“ mytest”
ex
mytest.txt
mytest.shp
mytest.bdf
mytest.shx
mylist = ["mytest.txt","mytest.shp","mytest.bdf","mytest.shx"]
mytest.txt
mytest.shp
mytest.bdf
mytest.shx
mytest.pjr
mylist = ["mytest.txt","mytest.shp","mytest.bdf","mytest.shx","mytest.pjr"]
正如您在問題中所說,您正在尋找glob
模塊 ,但擴展名上帶有通配符:
import glob
glob.glob("mytest.*")
例:
$ ls
a.doc a.pdf a.txt b.doc
$ python
Python 2.7.3 (default, Dec 18 2012, 13:50:09) [...]
>>> import glob
>>> glob.glob("a.*")
['a.doc', 'a.pdf', 'a.txt']
>>>
如果您還有其他名為mylist
文件,這些文件沒有所需的擴展名,那么這可能是一個更好的解決方案:
import glob
extensions = ["txt","shp","bdf","shx"] # etc
mylist = list()
for ext in extensions:
mylist += glob.glob("mylist.{}".format(ext))
甚至可能更容易:
mylist = [item for item in glob.glob('mylist.*') if item[-3:] in extensions]
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.