使用Smack XMPP發送內聯圖像

Question

我將要創建一個簡單的xmpp java客戶端應用程序，為此，我正在考慮使用Smack XMPP庫，該庫運行良好。

客戶端的一項功能應該是將嵌入式圖像發送到您的chatpartner。 我瀏覽了SMACK的javadoc，但無法找到如何使用SMACK / XMPP發送圖像或一般二進制數據的方法。 我並不是在說接收用戶必須接受的標准文件傳輸，而是在消息中可以發送的圖像。 SMACK / XMPP是否可能？ 有人可以提供例子嗎？

Answer 1

您可以通過使用smth使其默認為接受（不會提示用戶），例如：

final FileTransferManager manager = new FileTransferManager(connection); //Use your xmpp connection
manager.addFileTransferListener(new FileTransferListener() {
    public void fileTransferRequest(FileTransferRequest request) {
            IncomingFileTransfer transfer = request.accept();
            try {
                InputStream input = transfer.recieveFile();
                //This will be a binary stream and you can process it. Create image and display it inline in your chat app.
            } catch (XMPPException e) {
                e.printStackTrace();
            }
        }
    }

Answer 2

您可以嘗試以下鏈接： https : //www.javacodegeeks.com/2012/08/android-file-transfer-with-asmack-and.html

對於文件發送

FileTransferManager manager = new FileTransferManager(connection);
OutgoingFileTransfer transfer = manager.createOutgoingFileTransfer('usre2@myHost/Smack');
File file = new File(filenameWithPath);
try {
   transfer.sendFile(file, 'test_file');
     } catch (XMPPException e) {
       e.printStackTrace();
}
while(!transfer.isDone()) {
   if(transfer.getStatus().equals(Status.error)) {
      System.out.println('ERROR!!! ' + transfer.getError());
   } else if (transfer.getStatus().equals(Status.cancelled)
                    || transfer.getStatus().equals(Status.refused)) {
      System.out.println('Cancelled!!! ' + transfer.getError());
   }
   try {
      Thread.sleep(1000L);
   } catch (InterruptedException e) {
      e.printStackTrace();
   }
}
if(transfer.getStatus().equals(Status.refused) || transfer.getStatus().equals(Status.error)
 || transfer.getStatus().equals(Status.cancelled)){
   System.out.println('refused cancelled error ' + transfer.getError());
} else {
   System.out.println('Success');
}

文件接收：

FileTransferManager manager = new FileTransferManager(connection);
manager.addFileTransferListener(new FileTransferListener() {
   public void fileTransferRequest(final FileTransferRequest request) {
      new Thread(){
         @Override
         public void run() {
            IncomingFileTransfer transfer = request.accept();
            File mf = Environment.getExternalStorageDirectory();
            File file = new File(mf.getAbsoluteFile()+'/DCIM/Camera/' + transfer.getFileName());
            try{
                transfer.recieveFile(file);
                while(!transfer.isDone()) {
                   try{
                      Thread.sleep(1000L);
                   }catch (Exception e) {
                      Log.e('', e.getMessage());
                   }
                   if(transfer.getStatus().equals(Status.error)) {
                      Log.e('ERROR!!! ', transfer.getError() + '');
                   }
                   if(transfer.getException() != null) {
                      transfer.getException().printStackTrace();
                   }
                }
             }catch (Exception e) {
                Log.e('', e.getMessage());
            }
         };
       }.start();
    }
 });

Answer 3

您可以嘗試以下方法：

public boolean sendFiles(XMPPConnection con,String fullJID,String filePath){  
    File files=new File(filePath);  
    FileTransferManager fileManager=new FileTransferManager(con);  
    OutgoingFileTransfer sendfile=fileManager.createOutgoingFileTransfer(fullJID);  
    try {  
        sendfile.sendFile(files, "Sending file");  
        return true;  
    } catch (XMPPException e) {  
        e.printStackTrace();  
        return false;  
    }  
}  

public void receiveFiles(XMPPConnection con,final String filePath){  
    FileTransferManager fileManager=new FileTransferManager(con);  
    fileManager.addFileTransferListener(new FileTransferListener() {  
        @Override  
        public void fileTransferRequest(FileTransferRequest prequest) {  
            //System.out.println("The file received from: " + prequest.getRequestor());  
            System.out.println("filePath:"+filePath+"||FileName:"+prequest.getFileName());  
            file = new File(filePath +"\\" +prequest.getFileName());  
            request = prequest;  
            IncomingFileTransfer infiletransfer =request.accept();  
            try {  
                infiletransfer.recieveFile(file);  
                System.out.println("success!");  
            } catch (XMPPException e) {  
                e.printStackTrace();  
            }  
        }  
    });  
}