[英]Sql query for union of 2 tables
我陷入了疑問。 我有兩個表,並且兩個表都有一個共同的列,但是兩個表中的數據可能不同:
標簽1
+---------+------------+
| Sub | student_id |
+---------+------------+
| Math | 0033 |
| Science | 0034 |
| Geom | 0035 |
| Math | 0034 |
+---------+------------+
標簽2
+---------+----------+
| Sub | class_id |
+---------+----------+
| Science | 001 |
| Geom | 002 |
| Geom | 001 |
| Civics | 004 |
+---------+----------+
現在,我需要通過以下方式獲得結果:
+---------+----------------+--------------+
| Sub | Student(count) | Class(count) |
+---------+----------------+--------------+
| Math | 2 | 0 |
| Science | 1 | 1 |
| Geom | 1 | 2 |
| Civics | 0 | 1 |
+---------+----------------+--------------+
我想我必須使用union,並且可以在兩個不同的查詢中獲得結果,但是無法顯示上述最終表。
這就是我所擁有的:
select sub,count(*)as student_id from tab1
group by sub
union
select sub,count(*)as class_id from tab2
group by sub
但是我得到的是2列而不是3列。
任何幫助將不勝感激。
試試這個
SELECT AllSubs.Sub as Sub,
COUNT(DISTINCT tab1.Student_Id) as "Student(Count)",
COUNT(DISTINCT tab2.Class_Id) as "Class(Count)"
FROM
(SELECT DISTINCT Sub FROM tab1
UNION
SELECT DISTINCT Sub FROM tab2)AllSubs
LEFT JOIN tab1 ON tab1.Sub = AllSubs.Sub
LEFT JOIN tab2 ON tab2.Sub = AllSubs.Sub
GROUP BY AllSubs.Sub
該查詢從tab1和tab2中選擇所有不同的主題,然后與tab1和tab2左連接,然后計算不同的studdent_id並按主題對不同的class_id進行計數。
SELECT AllSubs.Sub as Sub,
COUNT(DISTINCT tab1.Student_Id) as "Student(Count)",
COUNT(DISTINCT tab2.Class_Id) as "Class(Count)",
COUNT(DISTINCT tab1.Student_Id) - COUNT(DISTINCT tab2.Class_Id) as difference
FROM
(SELECT DISTINCT Sub FROM tab1
UNION
SELECT DISTINCT Sub FROM tab2)AllSubs
LEFT JOIN tab1 ON tab1.Sub = AllSubs.Sub
LEFT JOIN tab2 ON tab2.Sub = AllSubs.Sub
GROUP BY AllSubs.Sub
ORDER BY difference DESC
如果只需要第一行,只需在查詢末尾添加LIMIT 1
。
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