從數據庫中獲取值不起作用

Question

我試圖從我的本地數據庫獲取一個特定的值，但似乎它是最重要的工作，這是我的代碼：

$acceptance = " SELECT acceptance_status FROM teams_0517 WHERE team_id=$team_id"; 
$acceptancex = mysql_query($acceptance);
mysql_close($connection);

if($acceptancex == 0)
{
    ob_clean();
    header('Location: index.php');
    ob_flush();
}
else
{
    ob_clean();
    header('Location: signup.php');
    ob_flush();
}

當我運行代碼時，php將跳過if條件並繼續執行其他語句，因此似乎$acceptance沒有值..有什么幫助嗎？

Answer 1

執行查詢后需要獲取結果。 看看如何獲取

試試這樣：

$acceptance = " SELECT acceptance_status FROM teams_0517 WHERE team_id=$team_id limit 1"; 
$result = mysql_query($acceptance);
$acceptancex = mysql_fetch_object($result); // fetch object


if($acceptancex->acceptance_status == 0)
{
    ob_clean();
    mysql_close($connection);
    header('Location: index.php');
    ob_flush();
}
else
{
    ob_clean();
    mysql_close($connection);
    header('Location: signup.php');
    ob_flush();
}

Answer 2

嘗試這個：-

$acceptance = " SELECT acceptance_status FROM teams_0517 WHERE team_id=$team_id limit 1"; 
$result = mysql_query($acceptance);
$acceptancex = mysql_fetch_object($result); // fetch object

if($acceptancex->acceptance_status == 0)
{
    $redirect = "index.php";
}
else
{
    $redirect = "signup.php";
}
mysql_close($connection);

ob_clean();
header('Location: '.$redirect);
ob_flush();