[英]i want to get next record of the table whenever clicking on button in swing form
[英]I want to automatically increase table row after clicking button
嗨,我的問題是自動增加表格行。 實際上,當我單擊GET按鈕時,產品類型和產品名稱值是從數據庫中獲取的。 在這里,獲得這些值之后,我將再次基於該ID給出另一個ID,以獲取值。 但這並沒有設置在另一行。 這是我的java
代碼和jsp
:
Class.forName("com.mysql.jdbc.Driver");
System.out.println("driver loaded");
System.out.println("Driver is loaded");
Connection con= (Connection) DriverManager.getConnection("jdbc:mysql://localhost:3306/charms?user=root&password=root");
System.out.println("Connection created");
Statement st =con.createStatement();
String query="select * from product where ProductType_v='"+a+"' and ProductId_v='"+b+"'";
ResultSet rs = (ResultSet)st.executeQuery(query);
int i=0;
while(rs.next())
{
i++;
request.getSession().setAttribute("edit","success");
request.getSession().setAttribute("proType ", rs.getString("ProductType_v"));
request.getSession().setAttribute("proId", rs.getString("ProductId_v"));
request.getSession().setAttribute("strength", rs.getString("Strength_v"));
request.getSession().setAttribute("proName", rs.getString("ProductName_v"));
request.getSession().setAttribute("brand", rs.getString("BrandName_v"));
request.getSession().setAttribute("generic", rs.getString("GenricName_v"));
request.getSession().setAttribute("uom", rs.getString("UOM_v"));
request.getSession().setAttribute("formE", rs.getString("FormE_v"));
request.getSession().setAttribute("presReqd", rs.getString("PresReqd_v"));
}
if(i==0)
{
request.getSession().setAttribute("edit", "fail");
}
}
catch(Exception e)
jsp code
<tr>
<td>
<input class="textfield-form-date-req" type="text" id="pro_type">
</td>
<%
if(editStatus =="success")
{
%>
<script type="text/javascript">
document.getElementById("pro_type").value='<%=session.getAttribute("proType")%>';
</script>
<%
}
<td>
<input class="textfield-form-date-req" type="text" id="pro_id">
</td>
<%
if(editStatus =="success")
{
%>
<scripttype="text/javascript">
document.getElementById("pro_id").value='<%=session.getAttribute("proName")%>';
</script>
<%
}
%>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
我已經用ajax
為您創建了一個樣本。 它從server side
獲取數據並將其附加到現有表中。
我使用的jar文件是,
jackson-all-1.9.0.jar-將Java對象轉換為json格式
servlet-api-2.4.jar-用於servlet
我的TableAppend.jsp
將是
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
<script
src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">
</script>
<script type="text/javascript">
$(document).ready(function() {
//alert("DOM is ready");
});
function sendData() {
$.ajax({
type : 'POST',
url : "TableAppend",
data : "name=" + $('#name').val() + "&age=" + $('#age').val()
+ "&sid=" + new Date(),
dataType : 'html',
success : function(result) {
//alert("Result ::::>>> "+result);
if(result != null && $.trim(result) != "" && result != undefined){
var json = JSON.parse(result);
//alert(json.name);
//alert(json.age);
appendToTable(json.name, json.age);
}
},
error : function(e) {
alert('Error in Processing');
}
});
}
function appendToTable(name, age) {
var tr = "<tr><td>" + name + "</td><td>" + age + "</td></tr>"
$('#mytable').append(tr);
}
</script>
</head>
<body>
Name :
<input type="text" id="name" name="name" /> Age :
<input type="text" id="age" name="age" />
<input type="button" value="Append to table" onclick="sendData()">
<br></br>
<br></br>
<br></br>
<table id="mytable" border="1">
<tbody>
<tr>
<th>Name</th>
<th>Age</th>
</tr>
<tr>
<td>HumanBeing</td>
<td>25</td>
</tr>
<tr>
<td>Saideep</td>
<td>26</td>
</tr>
</tbody>
</table>
</body>
</html>
我的TableAppend.java servlet
將是
public class TableAppend extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* Default constructor.
*/
public TableAppend() {
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
response.setCharacterEncoding("UTF-8");
response.setContentType("UTF");
PrintWriter out = response.getWriter();
request.setCharacterEncoding("UTF-8");
String name = request.getParameter("name");
String age = request.getParameter("age");
String json ="";
System.out.println("-----------------");
if(name != null && age != null){
TableAppendPojo obj = new TableAppendPojo();
obj.setName(name);
obj.setAge(age);
ObjectMapper mapper = new ObjectMapper();
json = mapper.writeValueAsString(obj);
System.out.println("json : "+json);
}
out.println(json);
}
}
然后, java class
將是
public class TableAppendPojo {
private String name;
private String age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getAge() {
return age;
}
public void setAge(String age) {
this.age = age;
}
}
注意:請在您的代碼中應用以上邏輯。 就您而言,您不需要從UI
提供數據。 您檢索來自數據database
中servlet
。所以請從轉換檢索數據database
到json
格式,並追加到table
。
希望這可以幫助。
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