[英]Spring, Hibernate, JUnit Annotated Entity
我試圖為我的JUnit
,Spring和Hibernate環境設置一個簡單的測試環境。 我還嘗試在Java中配置整個程序,暫時不要使用XML文件。
到目前為止,我能夠使用@Autowire
@Beans
,但是無法使用@Entity
。 我不斷收到一個例外,說我的實體未注冊。
這是我在做什么的一個示例:
JpaTestConfig.java
package com.springtest.test.configuration;
import java.util.Properties;
import javax.sql.DataSource;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor;
import org.springframework.jdbc.datasource.DriverManagerDataSource;
import org.springframework.orm.jpa.JpaTransactionManager;
import org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean;
import org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter;
import org.springframework.transaction.PlatformTransactionManager;
import org.springframework.transaction.annotation.EnableTransactionManagement;
@Configuration
@EnableTransactionManagement
public class JpaTestConfig {
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactoryBean(){
LocalContainerEntityManagerFactoryBean lcemfb
= new LocalContainerEntityManagerFactoryBean();
lcemfb.setDataSource(this.dataSource());
lcemfb.setPackagesToScan(new String[] {"com.jverstry"});
lcemfb.setPersistenceUnitName("MyTestPU");
HibernateJpaVendorAdapter va = new HibernateJpaVendorAdapter();
lcemfb.setJpaVendorAdapter(va);
Properties ps = new Properties();
ps.put("hibernate.dialect", "org.hibernate.dialect.HSQLDialect");
ps.put("hibernate.hbm2ddl.auto", "create");
lcemfb.setJpaProperties(ps);
lcemfb.afterPropertiesSet();
return lcemfb;
}
@Bean
public DataSource dataSource(){
DriverManagerDataSource ds = new DriverManagerDataSource();
ds.setDriverClassName("org.hsqldb.jdbcDriver");
ds.setUrl("jdbc:hsqldb:mem:testdb");
ds.setUsername("sa");
ds.setPassword("");
return ds;
}
@Bean
public PlatformTransactionManager transactionManager(){
JpaTransactionManager tm = new JpaTransactionManager();
tm.setEntityManagerFactory(this.entityManagerFactoryBean().getObject());
return tm;
}
@Bean
public PersistenceExceptionTranslationPostProcessor exceptionTranslation(){
return new PersistenceExceptionTranslationPostProcessor();
}
}
ServiceConfig.java
package com.springtest.test.configuration;
import com.springtest.services.UserService;
import com.springtest.services.UserServiceImpl;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
@Configuration
@ComponentScan(basePackages = {
"com.springtest.service"
})
public class ServiceConfig {
@Bean
public UserService getuserService() {
return new UserServiceImpl();
}
}
還有我的測試文件。 UserServiceTest.java
package com.springtest.test.services;
import static org.junit.Assert.*;
import org.junit.Test;
import org.springframework.beans.factory.annotation.Autowired;
import com.springtest.pojo.User;
import com.springtest.services.UserService;
import org.junit.runner.RunWith;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import com.springtest.test.configuration.*;
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(classes={ JpaTestConfig.class,
ServiceConfig.class})
public class UserServiceTest {
@Autowired
private UserService userService;
@Test
public void testCreateAndRetrieve() {
String json = "{\"firstName\": \"John\", \"lastName\": \"Doe\"}";
User user = userService.create(json);
assertEquals("John", user.getFirstName());
}
}
我的服務豆:
package com.springtest.services;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import javax.persistence.PersistenceContextType;
import javax.persistence.criteria.CriteriaQuery;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;
import com.google.gson.GsonBuilder;
import com.springtest.pojo.User;
@Service
public class UserServiceImpl implements UserService {
@PersistenceContext(type=PersistenceContextType.EXTENDED)
EntityManager em;
@Transactional
public User create(String json) {
User user = new GsonBuilder().create().fromJson(json, User.class);
em.persist(user);
return user;
}
}
還有我的Entity類:
package com.springtest.pojo;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
@Entity
public class User {
@Id
@GeneratedValue
private Integer id;
private String firstName;
private String lastName;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
}
總之,如何在Java類@Configuration
文件上注冊實體?
謝謝,
問題出在我的JpaTestConfiguration文件上的軟件包掃描程序。 更具體地說,這一行:
lcemfb.setPackagesToScan(new String[] {"com.springtest.pojo"});
是將瀏覽軟件包的@Entity
注釋類的軟件包。 謝謝@Rembo
的提示。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.