[英]MySql Query, Select greater than
我有一個名為faq_questions的表,其結構如下:
id int not_null auto_increment,
question varchar(255),
sort_order int
我正在嘗試構建一個給定排序順序的查詢,選擇具有下一個最高排序順序的行。
例:
id question sort_order
1 'This is question 1' 10
2 'This is question 2' 9
3 'This is another' 8
4 'This is another one' 5
5 'This is yet another' 4
好吧,所以想象一下我傳入5表示已知的排序順序(id 4),我需要它返回id為3的行。由於不能保證sort_order是連續的,所以我不能只選擇known_sort_order + 1。
謝謝!
看起來太簡單了,但它看起來像你需要的:
SELECT id,question FROM `questions`
WHERE `sort_order` > sort_order_variable
ORDER BY sort_order ASC
LIMIT 1
SELECT * FROM table_name WHERE sort_order > 5 ORDER BY sort_order ASC LIMIT 1
你可以使用TOP
或LIMIT
來做到這一點:
SELECT TOP 1 * FROM faq_questions
WHERE sort_order > 5
ORDER BY sort_order ASC
但這並不像優雅或便攜
SELECT *
FROM faq_questions AS f1
LEFT JOIN faq_questions AS f2
ON f1.sort_order > f2.sort_order
AND f2.sort_order = 5
LEFT JOIN faq_questions AS f3
ON f3.sort_order BETWEEN f1.sort_order AND f2.sort_order
WHERE f3.id IS NULL
SELECT
id, question, sort_order
FROM faq_questions
WHERE sort_order in
(SELECT
MIN(sort_order)
FROM faq_questions
WHERE sort_order > ?);
這似乎有效
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