[英]how do I sort a array of text by the last numberic character in javascript
我有一系列文本,例如this [building2, building1 , building3, building5, building4]
。
如何按最后一個數字字符對該數組進行排序,因此排序后的數組將為building1, building2, building3, building4, building5, building6
?
var array = ["building200", "building10", "building3", "building5", "building4"];
array.sort(function(a, b){
var char1 = a.substr(a.search(/\d+$/)); // get the last numbers
var char2 = b.substr(b.search(/\d+$/)); // get the last numbers
return parseInt(char1) - parseInt(char2); // sort by parsing to number
});
alert(array); // ["building3", "building4", "building5", "building10", "building200"]
a.search(/\\d/)
將返回遇到的第一個數字的索引,而a.substr(that_index)
將從a.substr(that_index)
切割字符串直到結尾。
如果數組具有長度不均勻的字符串(例如["buildingsss2", "buildisng1", "building3", "building5", "builsding4"]
希望有幫助!
您可以使用正則表達式\\d+
來獲取所有連續數字,然后通過將一個元素與另一個元素相減來比較兩個元素,如下所示
var data = [ 'building2', 'building10', 'building3', 'building5', 'building4' ];
data.sort(function(first, second) {
return /\d+/.exec(first)[0] - /\d+/.exec(second)[0];
});
console.log(data);
輸出量
[ 'building2', 'building3', 'building4', 'building5', 'building10' ]
注意:這比到目前為止發布的其他解決方案要好,因為即使數字大於9,也可以正常工作。
使用.sort()方法
var a = ['building2', 'building1' , 'building3', 'building5', 'building4'];
console.log(a.sort());
輸出量
["building1", "building2", "building3", "building4", "building5"]
不需要自定義功能
Array.sort
,使用:
['building2', 'building1', 'building3', 'building5', 'building4'].
sort(function(a,b){
return +( /\d{1,}$/.exec(a) || [0] )[0] -
+( /\d{1,}$/.exec(a) || [0] )[0];
}
);
這樣,您還可以對10多個建築物進行排序,例如
['building1', 'building12', 'building302', 'building205', 'building400']
並包含不以數字結尾的字符串
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