關於為什么的任何建議 </option> 標簽沒有在第二回顯結束時打印？

Question

打印第二個echo語句時不帶結束</option>標記。 但是可以正確打印其余代碼。 如果我檢查HTML，則將文本Any Publisher ...留在''單引號中。 謝謝

 function getPublishers (){

    $sql = "SELECT DISTINCT publisher FROM book ORDER BY publisher ASC";
    $rs = mysql_query($sql) or die(mysql_error());
    $rows = mysql_fetch_assoc($rs);
    $tot_rows = mysql_num_rows($rs);
    if($tot_rows>0){
        echo "<select name=\"srch_publisher\" id=\"srch_publisher\>\n";
        **echo "<option value\"\">Any Publisher&hellip;*</option>*\n";**
        do{
            echo "<option value=\"".$rows['publisher']."\">".$rows['publisher']."</option>";
        } while($rows = mysql_fetch_assoc($rs));
        echo "</select>";
    }
    mysql_free_result($rs);
}

Answer 1

您在id="srch_publisher"之后缺少id="srch_publisher" ：

echo "<select name=\"srch_publisher\" id=\"srch_publisher\>\n";
                                                         ↑
                                  missing closing quote (") at this position